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BARSIC [14]
3 years ago
14

Name each quadrilateral for which the statement is always true.

Mathematics
1 answer:
sertanlavr [38]3 years ago
3 0

Answer:

rhombus

Step-by-step explanation:

Rhombus has that equiangular and is equilateral but I'm not entirely sure about this...

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4 0
3 years ago
please help with maths work
prisoha [69]

Given:

In a right angle triangle ABC, \angle B=90^\circ,x=8.7\ m, and \theta = 45^\circ

To find:

The value of AC.

Solution:

In a right angle triangle,

\cos \theta =\dfrac{Adjacent}{Hypotenuse}

\cos \theta =\dfrac{BC}{AC}

\cos (45^\circ) =\dfrac{8.7}{AC}

\dfrac{1}{\sqrt{2}}=\dfrac{8.7}{AC}

On cross multiplication, we get

AC=8.7\times \sqrt{2}

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Therefore, the measure of AC is 12.304 m.

3 0
3 years ago
The reference desk of a university library receives requests for assistance. Assume that a Poisson probability distribution with
NISA [10]

Answer:

a) 0.125

b) 7

c) 0.875 hr

d) 1 hr

e) 0.875

Step-by-step explanation:l

Given:

Arrival rate, λ = 7

Service rate, μ = 8

a) probability that no requests for assistance are in the system (system is idle).

Let's first find p.

a) ρ = λ/μ

\frac{7}{8} = 0.875

Probability that the system is idle =

1 - p

= 1 - 0.875

=0.125

probability that no requests for assistance are in the system is 0.125

b) average number of requests that will be waiting for service will be given as:

λ/(μ - λ)

= \frac{7}{8 - 7}

= 7

(c) Average time in minutes before service

= λ/[μ(μ - λ)]

= \frac{7}{8(8 - 7)}

= 0.875 hour

(d) average time at the reference desk in minutes.

Average time in the system js given as: 1/(μ - λ)

= \frac{1}{(8 - 7)}

= 1 hour

(e) Probability that a new arrival has to wait for service will be:

λ/μ =

{7}{8}

= 0.875

5 0
4 years ago
How do you solve this? <br> rs/a = k for r
morpeh [17]

Answer:

Step-by-step explanation:

In  \frac{rs}{a}=k begin by multiplying both sides by a to get

rs = ak  and divide away the s to get

r=\frac{ak}{s}

8 0
3 years ago
9y-36=-15x in Slope intercept form
vodka [1.7K]
Look in the file below

6 0
4 years ago
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