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BARSIC [14]
3 years ago
14

Name each quadrilateral for which the statement is always true.

Mathematics
1 answer:
sertanlavr [38]3 years ago
3 0

Answer:

rhombus

Step-by-step explanation:

Rhombus has that equiangular and is equilateral but I'm not entirely sure about this...

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What is the cost of operating a 3.00-w electric clock for a year if the cost of electricity is $0.0900 per kw · h ?
brilliants [131]
We must take into account the following change of units:
 1kw = 1000w

1 year = 365 days

1 day = 24 hours
 Applying the change of units we have that the electric consumption for 1 year is given by:
 (3) * (1/1000) * (365) * (24) = 26.28 kw * h

 Then, the total cost is given by:
 (26.28) * (0.0900) = 2.3652

 Answer:
 
the cost of operating a 3.00-w electric clock for a year is:
 
$ 2.3652
8 0
3 years ago
.
stiv31 [10]

Answer:

A

Step-by-step explanation:

Hello There!

The y value of ABC was subtracted by 7 to get to the figure A'B'C'

So the rule for the given transformation would be

(x,y) ---> (x,y-7)

5 0
3 years ago
Find the unit rate.<br> 180 miles in 3 hours
leva [86]

Answer:

60 miles per hour

Step-by-step explanation:

First, put the equation in a fraction.

You would put 180 up top because people always say miles per hour not the other way around.

You can see the dividing line as your "per" and your "hour" would be the bottom number.  

To find the unit rate, you will divide the numerator (180) and the denominator (3).  

Your final answer should be 60 miles per hour.

\frac{180}{3} = \frac{60}{1}= 60

3 0
3 years ago
If $10,500 is deposited in a compound interest account paying 2.99% interest annually, how much will be in the account after 5 y
algol [13]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$10500\\ r=rate\to 2.99\%\to \frac{2.99}{100}\dotfill &0.0299\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &5 \end{cases} \\\\\\ A=10500\left(1+\frac{0.0299}{1}\right)^{1\cdot 5}\implies A=10500(1.0299)^5\implies A\approx 12166.47

5 0
3 years ago
You organize a garage sale. You have $30 at the beginning of the sale. You earn an average of $20 per hour. Write an equation th
LekaFEV [45]

30+(20x)=y

30 is the money you had from the start of the garage sale.

20 is what you are getting per hour

y equals the total money you are earning at the end of the garage sale

5 0
3 years ago
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