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ser-zykov [4K]
4 years ago
7

In physics class, Carrie learns that a force, F, is equal to the mass of an object, m, times its acceleration, a. She writes the

equation F=ma.
Using this formula, what is the acceleration of an object with F=7.92 newtons and m=3.6 kilograms? Express your answer to the nearest tenth.
Mathematics
2 answers:
Leviafan [203]4 years ago
8 0

Using the formula to solve for acceleration you divide force by mass.

Acceleration = 7.92 / 3.6 = 2.2

Ksivusya [100]4 years ago
7 0

Answer:

Acceleration: 2.2 m/s^2

Step-by-step explanation:

F=M/A

7.92/ 3.6

2.2.

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3y''-6y'+6y=e*x sexcx
Simora [160]
From the homogeneous part of the ODE, we can get two fundamental solutions. The characteristic equation is

3r^2-6r+6=0\iff r^2-2r+2=0

which has roots at r=1\pm i. This admits the two fundamental solutions

y_1=e^x\cos x
y_2=e^x\sin x

The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

y_p=u_1y_1+u_2y_2

where

u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx
u_2=\displaystyle\frac13\int\frac{y_1e^x\sec x}{W(y_1,y_2)}\,\mathrm dx

and W(y_1,y_2) is the Wronskian of the fundamental solutions. We have

W(e^x\cos x,e^x\sin x)=\begin{vmatrix}e^x\cos x&e^x\sin x\\e^x(\cos x-\sin x)&e^x(\cos x+\sin x)\end{vmatrix}=e^{2x}

and so

u_1=-\displaystyle\frac13\int\frac{e^{2x}\sin x\sec x}{e^{2x}}\,\mathrm dx=-\int\tan x\,\mathrm dx
u_1=\dfrac13\ln|\cos x|

u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx
u_2=\dfrac13x

Therefore the particular solution is

y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x

so that the general solution to the ODE is

y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x
7 0
3 years ago
PLEASE ANSWER IMMEDIATELY <br>find the area of the following shape​
STatiana [176]

Answer:

i think the answer is 51

6 0
4 years ago
MARKING BRAINLY PLEASE JUST HELPPP
Keith_Richards [23]

Answer:

i don't it is correct or not........

Step-by-step explanation:

The Mass of Earth = 5.9742 × 1024 kilograms == == The Earth is (As of May 2000) is thought to be approximately 5.972 sextillion (5,972,000,000,000,000,000,000) metric tons.

A metric ton is a thousand kilograms, or 2,204.62 pounds.

Approximately 6,000,000,000,000,000,000,000,000 (6x1024) kilograms.

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