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jek_recluse [69]
3 years ago
5

Given the following rectangle and circle, at what approximate value of x are the two areas equal? Show work and explain all step

s.

Mathematics
1 answer:
suter [353]3 years ago
7 0

Answer:

x ≈ 1.28

Step-by-step explanation:

I just took the exam:

Area of rectangle =(3x-1)(x+6), Area of circle = PI(x+1)^2. If you graph these and find where they intersect, you will get x ≈ 1.28.

I hope this helped! :)

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Answer:

The equation is not linear. So the slope does not exist. Not linear.


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A restaurant is making hamburgers. The cooks use two thirds
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36x 2/3= 24 so u would have to use 24lbs of beef
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4 Consider the triangle below.
Maurinko [17]
<h2>=>> <u>Solution (part A</u>) :</h2>

Given :

▪︎Triangle AMG is an isosceles triangle.

▪︎Measure of segment AM = (x+1.4) inches

▪︎Measure of segment MG = (2x+0.1) inches

▪︎Measure of segment AG = (3x-0.4) inches

▪︎segment AG is the base of triangle AMG.

Since AG is the base of the isosceles triangle AMG, segment AM and segment MG will be equal.

Which means :

= \tt x + 1.4 = 2x + 0.1

= \tt x + 1.4 - 0.1 = 2x

=  \tt \: x + 1.3 = 2x

= \tt 1.3 = 2x - x

\color{plum} \hookrightarrow  \tt x = 1.3

Thus, the value of x = 1.3

Therefore :

▪︎The value of x = 1.3

<h2>=>> <u>Solution (Part B)</u> :</h2>

We know that :

▪︎The value of x = 1.3

Which means :

The length of the leg AM :

= \tt x + 1.4

= \tt 1.3 + 1.4

\color{plum} \tt leg \: AM= 2.7 \: inches

Thus, the length of the leg AM = 2.7 inches

The length of leg MG :

= \tt 2x + 0.1

=  \tt2 \times 1.3 + 0.1

= \tt 2.6 + 0.1

\color{plum} \tt\: leg \:MG = 2.7 \: inches

Thus, the length of the leg MG = 2.7 inches

Since the measure of the two legs are equal (2.7=2.7), we can conclude that we have found out the correct length of each leg.

Therefore :

▪︎Measure of leg AM = 2.7 inches

▪︎Measure of leg MG = 2.7 inches

<h2>=>> <u>Solution </u><u>(</u><u>part C</u><u>)</u> :</h2>

We know that :

Value of x = 1.3

Then, measure of the base AG :

=  \tt 3x - 0.4

= \tt 3 \times 1.3 - 0.4

= \tt 3.9 - 0.4

\color{plum}\tt \: Base  \: AG = 3.5 \:  inches

Thus, the measure of the base = 3.5 inches

Therefore :

▪︎ the length of base AG = 3.5 inches.

6 0
3 years ago
Which statements are true about these lines? Select three<br> options.
gayaneshka [121]

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6 0
2 years ago
Please help me with this
Len [333]

Answer:

60 degrees

Step-by-step explanation:

To first solve this problem, we need to figure out the size of an interior angle for a regular hexagon.

This can be done with the formula :

angle = \frac{(n-2)*180}{n} , with n being the number of sides

A hexagon has 6 sides so here is how we would solve for the interior angle:

\frac{(6-2)*180}{6}=120 , with n= 6 sides

Now that we know that each interior angle in the hexagon is 120 degrees, we can now turn our attention to the rhombus.

The opposite angles of the rhombus are congruent, so the two larger obtuse angles are congruent, and so are the two smaller acute angles.

It is also important to note that a rhombus is a quadrilateral, so all of its interior angles add up to 360 degrees.

Looking at the rhombus, we already know one of the angles because it is shared by the interior angle of the hexagon, so the two larger angles in the rhombus are both 120 degrees.

But what about the smaller angles? All we need to do is subtract the two larger angles form 360 and divide by 2 to find the angle.

\frac{360-2(120)}{2} = 60 , so the smaller angle in the rhombus is 60 degrees.

Now that we know both the interior angle and smaller angle of the rhombus, we can find x.

Together, angle x and the angle adjacent to it makes up an interior angle of the hexagon, so x plus that angle is going to equal to 120 degrees.

All we need to do is solve for x:

x+60=120

x=120-60

x = 60 degrees

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3 years ago
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