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puteri [66]
3 years ago
6

Consider an economy with only two goods: bread and wine. In 1982, the typical family bought 4 loaves of bread at 50¢ per loaf an

d 2 bottles of wine for $9 per bottle. In Year X, bread cost 75¢ per loaf and wine cost $10 per bottle. The CPI for Year X (using a 1982 base year) is:
Business
1 answer:
mylen [45]3 years ago
7 0

Answer:

115

Explanation:

Data provided in the  question:

Number of breads bought = 4

Number of wine bottles bought = 2

Cost of bread in year 1982 = 50 cents = $0.5

Cost of wine bottle in year 1982 = $9

Cost of bread in year X = 75 cents = $0.75

Cost of wine bottle in year X = $10

Now,

The CPI is calculated as:

CPI = \frac{\textup{Cost of basket in the given year (i.e year X)}}{\textup{Cost of basket in the base year (i.e 1982)}}\times100

thus,

CPI for year X = \frac{\$0.75\times4+\$10\times2}{\$0.5\times4+\$9\times2}\times100

or

CPI for year X = \frac{\$23}{\$20}\times100

or

CPI for year X = 1.15 × 100 = 115

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The Centers for Disease Control and Prevention (CDC) defines a healthy sleep duration
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a. The point estimate of the married people that sleep well is = 0.6299. The confidence interval for the mean hours of sleep for those that have never been married but report good sleep is 0.6186, 0.6412

b. The point estimate of the number of hours for people that have never been married = 7.2257

95% confidence interval for the mean number of  hours of sleep for those who have never been married = 7.2065, 7.2447

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a. The point estimate

P=\frac{Xp}{n}

Xp = successes\\n = sample size\\

Those who have never been married n = 7044

Xp = those who sleep for 7 hours at least

To get Xp, the <u>excel function </u>

Countif(range, criteria)

Countif(A:A, >=7)

This gives Xp = 4437

Point estimate =

\frac{4477}{7044}

= 0.6299

The point estimate of the married people that sleep well is = 0.6299

At 95% interval of confidence,

α = 1-0.95 = 0.05

α/2 = 0.05/2 = 0.025

Z0.025 = 1.96 ( Use the standard probability normal table)

Margin of Error

=M.E = 1.96\sqrt \frac{0.6299(1-0.6299)}{7044} \\\\= 1.96\sqrt{0.000033} \\\\1.96*0.0057

= 0.0113

The 95% confidence interval

= 0.6299 - 0.0113 , 0.6299 + 0.0113

= 0.6186, 0.6412

The confidence interval for the mean hours of sleep for those that have never been married is 0.6186, 0.6412

b. Sample mean

x = ∑x/n

x = number of sleep of the never been married

Mean is calculated using excel function

Average(range)

Average(a:a)

This gives the sample mean = 7.2257

The point estimate of the number of hours for people that have never been married = 7.2257

<u>Standard deviation</u> using excel =

Stdev(A:A) = 0.8211

Margin of error =1.96*\frac{0.8211}{\sqrt{7044} }

= 0.0192

The<u> confidence interval</u> =

= 7.2257-0.0192, 7.2257+0.0192

= 7.2065, 7.2447

95% confidence interval for the mean number of  hours of sleep for those who have never been married = 7.2065, 7.2447

c. From the available data, the mean number of sleep per day that is gotten from the 4437 people that are unmarried and sleep healthily for at least 7 hours = 34295.1

Mean = 34295.1/4437

= 7.729

the estimated number of sleep for those that have never been married = 7.729 hours

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