Answer: A) 20.9 ; B) 34years
Step-by-step explanation:
Given the following :
AGE (X) - - - - - - - 19 - -20 - - - 21 - - - 22 - - - 23
FREQUENCY (F) - 2 - - 3 - - - - 1 - - - - 4 - - - - 1
A)
MEAN(X) = [AGE(X) × FREQUENCY (F)] ÷ SUM OF FREQUENCY
F*X = [(19 * 2) + (20 * 3) + ( 21 * 1)+(22 * 4)+(23 * 1)]
= 38 + 60 +21 + 88 + 23 = 230
SUM OF FREQUENCY = 2 + 3 + 1 + 4 + 1= 11
MEAN(X) = 230 / 11
X = 20.9
B)
WHEN A NEW PLAYER WAS ADDED :
MEAN (X) = 22
Let age of new player = y
Sum of Ages = 19 + 19 +20 + 20 + 20 + 21 + 22 + 22 + 22 + 22 + 23 + y
Number of players = 11 + 1 = 12
Mean(x) = sum of ages / number of players
New mean (x) = 22
x = (230 + y) / 12
22 = (230 + y) / 12
Cross multiply
264 = 230 + y
y = 264 - 230
y = 34 years
Step-by-step explanation:
As we have to use the number 0-6 once to make 2 equivalent ratios.
so lets solve the problem.
Determining first equivalent ratio
as
and
so
Therefore, first equivalent ratio

Determining second equivalent ratio

as

and

Therefore, second equivalent ratio

The picture in the attached figure
we know that
m ∠ 6=123.5°
m ∠6+m∠2=180°-------> by supplementary angles
so
m∠2=180-m∠6-----> 180-123.5------> m∠2=56.5°
m∠1=m∠2--------> by corresponding angles
so
m∠1=56.5°
the answer ism∠1 is 56.5°