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nika2105 [10]
3 years ago
9

Use substitution to solve the system of equation x=y+6 x+y=10

Mathematics
2 answers:
Volgvan3 years ago
7 0

Answer:

x=8

y=2

Step-by-step explanation:

x+y=10

(y+6)+y=10

2y+6=10

2y=4

y=2

x=y+6

x=2+6

x=8

DiKsa [7]3 years ago
6 0
X = 8
Y = 2 Your welcomeeeeee
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Write an exponential function to describe the given sequence of numbers.
andriy [413]

Answer:

  a(n) = 9·6^(n-1)

Step-by-step explanation:

The general term a(n) of a geometric sequence with first term a(1) and common ratio r is given by ...

  a(n) = a(1)·r^(n-1)

Your sequence has first term 9 and common ratio 54/9 = 6, so the function describing it is ...

  a(n) = 9·6^(n-1)

5 0
3 years ago
How do you solve this ???
galina1969 [7]
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Then you plug in the costs of the video games into Janets equation 120=3x+y
(x= video games and y=used video games)
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3 0
3 years ago
a hotel has a number of meeting rooms,m, available for events. each meeting room has 325 chairs. write an equation to represent
liq [111]
C=325m
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6 0
4 years ago
Find an upper limit for the zeroes 2x^4 -7x^3 + 4x^2 + 7x - 6 = 0
erik [133]

<u>Answer-</u>

2 is the upper limit for the zeros.

<u>Solution-</u>

The given function f(x) is,

2x^4 -7x^3 + 4x^2 + 7x - 6 = 0

For calculating the zeros,

\Rightarrow f(x)=0

\Rightarrow 2x^4 -7x^3 + 4x^2 + 7x - 6 = 0

\Rightarrow 2x^4-4x^3-3x^3+6x^2-2x^2+ 4x+3x-6=0

\Rightarrow 2x^3(x-2)-3x^2(x-2)-2x(x-2)+3(x-2)=0

\Rightarrow (x-2)(2x^3-3x^2-2x+3)=0

\Rightarrow (x-2)(x^2(2x-3)-1(2x-3))=0

\Rightarrow (x-2)(x^2-1)(2x-3)=0

\Rightarrow (x-2)(x+1)(x-1)(2x-3)=0

\Rightarrow x-2=0,\ x+1=0,\ x-1=0,\ 2x-3=0

\Rightarrow x=2,\ x=-1,\ x=1,\ x=\frac{3}{2}

From all the 4 roots, it can be obtained that 2 is the greatest zero.

7 0
3 years ago
In 2decimal places 39.98015​
Morgarella [4.7K]

Answer:

39.98

Explanation:

39.98015​

0 < 5, so 2nd decimal stays at 8

6 0
3 years ago
Read 2 more answers
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