3 years ago

PLS FAST In a right triangle, angle A and angle B are acute, find the value of sinB given tanB=4/3.

1 answer:

5 0

Answer:

sinB= 4/5

Step-by-step explanation:

tan= opposite/ adjacent

3^2+4^2= hypotenuse^2 so hypotenuse=5

sin= opposite/ hypotenuse

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