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BabaBlast [244]
2 years ago
5

ok, so, if i have one F in math, will i fail 6th grade? for references, i live in the Hillsborough county district (in florida)

since some districts are different. i am rwally worried about this, thank you!​
Mathematics
1 answer:
olchik [2.2K]2 years ago
8 0

Answer: I do not think that failing one class will effect your entire 6th grade year. Although, this is best discussed with your teachers or parents/guardians.

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The athletic director of a college would like to reduce the number of injuries of her athletes. She believes that the ideal amou
kifflom [539]

Answer:

So it makes sense that students would need more sleep, especially athletes. I think the conclusion should be that the data supported the hypothsis. Otherwise, students would have more injuries when they sleep, which is obviously not the case.

Step-by-step explanation:

8 0
3 years ago
How much money would you need to deposit today at 7% annual interest
Monica [59]

Answer:

$33,090.

Step-by-step explanation:

The formula is A = P( 1 + r/2)^2n so we have:

50,000 = P(1 + 0.07/2)^(6*2)

50000 = P * 1.035^12

P = 50000/ 1.035^12

= $33,090 to the nearest dollar.

4 0
3 years ago
I’ll give u brainiest pls help me im so lost
Vlad1618 [11]

Answer:

(f o g)(4)=27

Step-by-step explanation:

(f o g)(4)=2x+5

f(g(4))=2x+5

f(4²-2(4)+3)=2x+5

f(16-8+3)=2x+5

f(8+3)=2x+5

f(11)=2x+5

f(11)=2(11)+5

f(11)=22+5

f(11)=27

Therefore, (f o g)(4)=27

3 0
3 years ago
(2*)2-3×2*+2=0<br>4m-15°(×)m+75°​
Valentin [98]

Answer:

First, we write the augmented matrix.

⎡

⎢

⎣

1

−

1

1

2

3

−

1

3

−

2

−

9

|

8

−

2

9

⎤

⎥

⎦

Next, we perform row operations to obtain row-echelon form.

−

2

R

1

+

R

2

=

R

2

→

⎡

⎢

⎣

1

−

1

1

0

5

−

3

3

−

2

−

9

|

8

−

18

9

⎤

⎥

⎦

−

3

R

1

+

R

3

=

R

3

→

⎡

⎢

⎣

1

−

1

1

0

5

−

3

0

1

−

12

|

8

−

18

−

15

⎤

⎥

⎦

The easiest way to obtain a 1 in row 2 of column 1 is to interchange \displaystyle {R}_{2}R

​2

​​  and \displaystyle {R}_{3}R

​3

​​ .

Interchange

R

2

and

R

3

→

⎡

⎢

⎣

1

−

1

1

8

0

1

−

12

−

15

0

5

−

3

−

18

⎤

⎥

⎦

Then

−

5

R

2

+

R

3

=

R

3

→

⎡

⎢

⎣

1

−

1

1

0

1

−

12

0

0

57

|

8

−

15

57

⎤

⎥

⎦

−

1

57

R

3

=

R

3

→

⎡

⎢

⎣

1

−

1

1

0

1

−

12

0

0

1

|

8

−

15

1

⎤

⎥

⎦

The last matrix represents the equivalent system.

x

−

y

+

z

=

8

y

−

12

z

=

−

15

z

=

1

Using back-substitution, we obtain the solution as \displaystyle \left(4,-3,1\right)(4,−3,1).First, we write the augmented matrix.

⎡

⎢

⎣

1

−

1

1

2

3

−

1

3

−

2

−

9

|

8

−

2

9

⎤

⎥

⎦

Next, we perform row operations to obtain row-echelon form.

−

2

R

1

+

R

2

=

R

2

→

⎡

⎢

⎣

1

−

1

1

0

5

−

3

3

−

2

−

9

|

8

−

18

9

⎤

⎥

⎦

−

3

R

1

+

R

3

=

R

3

→

⎡

⎢

⎣

1

−

1

1

0

5

−

3

0

1

−

12

|

8

−

18

−

15

⎤

⎥

⎦

The easiest way to obtain a 1 in row 2 of column 1 is to interchange \displaystyle {R}_{2}R

​2

​​  and \displaystyle {R}_{3}R

​3

​​ .

Interchange

R

2

and

R

3

→

⎡

⎢

⎣

1

−

1

1

8

0

1

−

12

−

15

0

5

−

3

−

18

⎤

⎥

⎦

Then

−

5

R

2

+

R

3

=

R

3

→

⎡

⎢

⎣

1

−

1

1

0

1

−

12

0

0

57

|

8

−

15

57

⎤

⎥

⎦

−

1

57

R

3

=

R

3

→

⎡

⎢

⎣

1

−

1

1

0

1

−

12

0

0

1

|

8

−

15

1

⎤

⎥

⎦

The last matrix represents the equivalent system.

x

−

y

+

z

=

8

y

−

12

z

=

−

15

z=1

Using back-substitution, we obtain the solution as \displaystyle \left(4,-3,1\right)(4,−3,1).

7 0
2 years ago
What is the missing angle in this quadrilateral?
kobusy [5.1K]

Answer:

108

Step-by-step explanation:

65+110+87=252

360(Total angle of quadrilaterals)-252=108

7 0
3 years ago
Read 2 more answers
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