3 years ago

2(5x + 3) -x + 3 = 18

Mathematics

1 answer:

Dvinal [7]3 years ago

7 0

Answer:

x = 1

Step-by-step explanation:

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Pls help me........ I tried lol

diamong [38]

its step 2 he did not subtract it right hope this helps and have a great day and get some sleep lol

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2 years ago

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Vectors...<br><br> Let u = <-3, -5>, v = <-3, 1>. Find u + v.

Anni [7]

-3 + -3 = 0
-5 + 1 = -4
vector = < 0,-4 >

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2 years ago

Help me please!!!!!!!!!!!!!!!!

Sav [38]

Answer:

x=-4 and y=4

Step-by-step explanation:

(6x+9y)-(6x+7y)=12-4=8

--> 9y-7y=8

-->2y=8-->y=4

-->6x+7×4=4 -->x=-4

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2 years ago

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What is the equation of a line that is perpendicular to -1 +3y=9 and passes through the point (-3, 2)?

kati45 [8]

Answer:

y-2 = 3/10(x+3)

Step-by-step explanation:

3y = 10

y = 10/3

looking for perpendicular so slope = 3/10

using the given point

y-2 = 3/10(x+3)

6 0

2 years ago

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A ball is thrown into the air with a velocity of 34 ft/s. It's height in feet after t seconds is given by y=34t-26(t)^2. Find th

kkurt [141]

Answer:

The average velocity of the ball at the given time interval is -122.3 ft/s

Step-by-step explanation:

Given;

velocity of the ball, v = 34 ft/s

height of the ball, y = 34t - 26t²

initial time, t₀ = 3 seconds

final time, t = 3 + 0.01 = 3.01 seconds

At t = 3 s

y(3) = 34(3) - 26(3)² = -132

The average velocity of the ball in ft/s is given as;

$V_{avg} = \frac{y(3.01)-y(3)}{3.01 -3}\\\\V_{avg} = \frac{34(3.01)-26(3.01)^2-y(3)}{3.01 -3}\\\\V_{avg} = \frac{-133.223-y(3)}{0.01}\\\\V_{avg} = \frac{-133.223-(-132)}{0.01}\\\\V_{avg} =\frac{-1.223}{0.01}\\\\V_{avg} = -122.3 \ ft/s$

Therefore, the average velocity of the ball at the given time interval is -122.3 ft/s

8 0

3 years ago