Answer:
The coefficients are;
1,28,378 and 3,276
Step-by-step explanation:
For the binomial expansion, when we talk of the coefficients, we mean the whole numbers that stands before the alphabets
For example, the coefficient of x in 2x is 2
Back to the question;
(x + y)^28
= 28C0 x^28y^0 + 28C1 X^27y^1 + 28C2 x^26y^2 + 28C3 x^25y^3 + ..........
So the coefficients we are looking for are;
28C0 = 1
28C1 = 28
28C2 = 378
28C3 = 3,276
Kindly note that 28C0 is read as 28 combination zero and so on
Yes it is
you can solve it dividing 4 <span>÷ 16 and you have 0.25</span>
I don't know, this is tricky
B because it’s the only true one and more than have of the weights are less than 12
