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3 years ago

More Acellus help please

Mathematics

2 answers:

elena-s [515]3 years ago

6 0

Answer:

it would be the first box

Step-by-step explanation:

sashaice [31]3 years ago

4 0

Answer:

Number 1 would be a line, you can put values of x and you will get values of y which give you points of that plot, or viceversa.

Number 2 is an horizontal line, as y remains the same all time, in this case, we find an horizontal line which covers all the x-axis.

Number 3 is a vertical line, as x remains the same all time, in this case, we find a vertical line which covers all the y-axis

So the solution is the third box

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Part 4. NO LINKS!! Find the area of the shaded area shown. SHOW WORK PLEASE !! #21

SIZIF [17.4K]

Area of square

32²
1024

Radius of each circle

32/4/2
8/2
4

Area of 16 circles

16πr²
16π(4)²
16π(16)
256π
803.8cm²

Area of shaded region

1024-803.8
220.2cm²

5 0

2 years ago

Read 2 more answers

What is the simplified expression for –3cd – d(2c – 4) – 4d?

kompoz [17]

–3cd – d(2c – 4) – 4d
= –3cd – 2cd + 4d – 4d
= -5cd

answer
A:–5cd

3 0

3 years ago

36 to the power -1/2

IRISSAK [1]

0.166667
it was rounded

6 0

4 years ago

4. What is the volume of the pyramid? 7 ft 9 ft 10 ft

xz_007 [3.2K]

Pyramids and cones have volumes which are one third of their matching cuboids and cylinders.

The volume of this pyramid = (7 x 9 x 10)/3 = 630 / 3 = 210 cu ft

8 0

3 years ago

Solve 2x^2 + x - 4 = 0 X2 +

damaskus [11]

Answer:

$\large \boxed{\sf \ \ x = -\dfrac{\sqrt{33}+1}{4} \ \ or \ \ x = \dfrac{\sqrt{33}-1}{4} \ \ }$

Step-by-step explanation:

Hello, please find below my work.

$2x^2+x-4=0\\\\\text{*** divide by 2 both sides ***}\\\\x^2+\dfrac{1}{2}x-2=0\\\\\text{*** complete the square ***}\\\\x^2+\dfrac{1}{2}x-2=(x+\dfrac{1}{4})^2-\dfrac{1^2}{4^2}-2=0\\\\\text{*** simplify ***}\\\\(x+\dfrac{1}{4})^2-\dfrac{1+16*2}{16}=(x+\dfrac{1}{4})^2-\dfrac{33}{16}=0$

$\text{*** add } \dfrac{33}{16} \text{ to both sides ***}\\\\(x+\dfrac{1}{4})^2=\dfrac{33}{16}\\\\\text{**** take the root ***}\\\\x+\dfrac{1}{4}=\pm \dfrac{\sqrt{33}}{4}\\\\\text{*** subtract } \dfrac{1}{4} \text{ from both sides ***}\\\\x = -\dfrac{1}{4} -\dfrac{\sqrt{33}}{4} \ \ or \ \ x = -\dfrac{1}{4} +\dfrac{\sqrt{33}}{4}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

4 0

4 years ago