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leonid [27]
4 years ago
11

Solve for x. 2x-4/10 = 2x/20

Mathematics
1 answer:
Nonamiya [84]4 years ago
7 0
<span>I think it's x=<span>419 well i could be wrong just an elementary eight year old</span></span>
You might be interested in
Given that (-5,-6) is on the graph of f(x), find the corresponding point for this function -1/3f(x).
masya89 [10]
<h3>Answer:  (-5, 2)</h3>

Explanation:

We multiply the y coordinate by -1/3 because of the notation (-1/3)*f(x). Recall that y = f(x). The x coordinate stays the same.

5 0
2 years ago
NEED HELP HERE ASAP<br><br> 6. Find the cube roots of 27(cos 330° + i sin 330°).
VLD [36.1K]
<span>we have that

the cube roots of 27(cos 330° + i sin 330°) will be
</span>∛[27(cos 330° + i sin 330°)]

we know that
e<span>^(ix)=cos x + isinx
therefore
</span>∛[27(cos 330° + i sin 330°)]------> ∛[27(e^(i330°))]-----> 3∛[(e^(i110°)³)]
3∛[(e^(i110°)³)]--------> 3e^(i110°)-------------> 3[cos 110° + i sin 110°]

z1=3[cos 110° + i sin 110°]

 cube root in complex number, divide angle by 3
360nº/3 = 120nº --> add 120º for z2 angle, again for z3
<span>therefore
</span>
z2=3[cos ((110°+120°) + i sin (110°+120°)]------ > 3[cos 230° + i sin 230°]

z3=3[cos (230°+120°) + i sin (230°+120°)]--------> 3[cos 350° + i sin 350°]
<span>
the answer is 

</span>z1=3[cos 110° + i sin 110°]<span>

</span>z2=3[cos 230° + i sin 230°]

z3=3[cos 350° + i sin 350°]<span>

</span>
7 0
4 years ago
Will give brainliest to correct first answer
xxTIMURxx [149]
The answer is 24 two ways you can find it is one by dividing or two my multiplying the reciprocal
6 0
3 years ago
Read 2 more answers
Can anyone help me on this please?
rjkz [21]
\dfrac{4a^3b^2+2a^2b^2+3ab}{ab}=\dfrac{4a^3b^2}{ab}+\dfrac{2a^2b^2}{ab}+\dfrac{3ab}{ab}=4a^2b+2ab+3
8 0
3 years ago
This is review, please help it’s due tomorrow!
Svet_ta [14]
I dont see anything
3 0
3 years ago
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