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kicyunya [14]
3 years ago
7

Can someone tell me the answer to this

Mathematics
1 answer:
geniusboy [140]3 years ago
8 0

Answer:

1.423 x 10^{12}

5.78 x 10^{-6}

Step-by-step explanation:

Scientific notation is a way of denoting a quantity as a single-digit number followed by decimals, times a base of ten.

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An investor has an account with stock from two different companies. Last year, his stock in Company A was worth $7200 and his st
Ronch [10]

Answer:

22.7%

Explanation:

Given that last year stock for company A was $7200

The stock for company B last year was worth $3510

Stock in company A decreased by 24%

This means the new value of stock for company A became;

(100-24)/100 *$7200

76/100*$7200

0.76*7200 =$5472

Stock in company B decreased by 20%

This means the new value of stock for company B became;

(100-20)/100 *$3510

80/100*$3510

0.8*$3510

$2808

Original investors stock value was = $7200+$3510 =$10710

New investors stock value is = $5472+$2808=$8280

Decrease in value of stock = $10710-$8280 =$2430

percentage decrease in stock value = decrease in stock/original value of stock *100%

=2430/10710 *100 =22.689

=22.7%

4 0
3 years ago
Solve the inequality 9(x - 3) < 4(x + 10).
disa [49]
X<67/5     :) do u need the work or nah
7 0
3 years ago
Read 2 more answers
In the year 2000, the average cost of a computer could be modeled by the equation C = -5t2 + 750, where t is the number of years
elena55 [62]

Answer:

\Delta C=-5t^2-250

Step-by-step explanation:

Given:

The average cost of a computer in the year 2000 is given as:

C=-5t^2+750

The average cost of a computer in the year 2008 is given as:

C=-10t^2+500

Now, the difference in average cost between the years 2008 and 2000 can be calculated by subtracting the average cost in 2000 from the average cost in 2008.

Framing in equation form, we get:

Difference in average cost (ΔC) is given as:

\Delta C=C_{2008}-C_{2000}\\\\\Delta C= (-10t^2+500)-(-5t^2+750)\\\\\textrm{Distributing the megative sign inside the second polynomial, we get:}\\\\\Delta C=-10t^2+500+5t^2-750\\\\\textrm{Grouping like terms, we get}\\\\\Delta C=(-10t^2+5t^2)+(500-750)\\\\\Delta C=-5t^2-250

Therefore, the difference in the costs for a computer between 2008 and 2000 is \Delta C=-5t^2-250

7 0
4 years ago
Find the quotient. (i'll give 30 points)
marissa [1.9K]
Your question is a bit confusing, but the answer (as in the question is -32.76/-3.6) is 9.1.
Hope that helps!
7 0
3 years ago
What is the value of s in the equation 3 r equals 10 plus 5 s, when r equals 10?
Artemon [7]

Answer:

s = 4

Step-by-step explanation:

3r = 10 + 5s

3×10 = 10 + 5s

5s = 30 - 10

5s = 20

s = 20 : 5

s = 4

7 0
3 years ago
Read 2 more answers
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