Please I need help with this ASAP

How many numbers are equal to the sum of two odd, one digit numbers

Paul [167]

Here is a list of the odd number paired

1+3, 1+5, !+7, and !+9 (there are 4 unique sums - 4, 6,8 and 10)
3+5, 3+7, 3+9 (notice I did not pair 3 with 1 and the the only new sum is 12)
5+7, 5+9 (the only new sum is 14)
7+9 (16 is a new sum)

The sums (no repeats) are 4,6,8,10,12,14 and 16 for a total of seven numbers.

5 0

3 years ago

What is the range of the function y = x2?

den301095 [7]

The range of the function y = x2 is all real numbers, y, such that y ≥ 0.

3 0

2 years ago

An elliptical-shaped path surrounds a garden, modeled by quantity x minus 20 end quantity squared over 169 plus quantity y minus

Margaret [11]

The <em>maximum</em> distance between any two points of the ellipse is 34 feet.

<h3>Procedure - Determination of the distance between two points of a ellipse</h3>

The maximum distance between any two points of a ellipse is the <em>maximum</em> distance between the ends of the ellipse along the <em>longest</em> axis, which is parallel to the y-axis in this case.

In addition, the equation of the ellipse in <em>standard</em> form is defined by this formula:

$\frac{(x-h)^{2}}{a^{2}} + \frac{(y-k)^{2}}{b^{2}} = 1$ (1)

Where:

$h, k$ - Coordinates of the center of the ellipse.
$a$ , $b$ - Lengths of each semiaxis.

Hence, the maximum distance ( $d_{max}$ ), in feet, is calculated by this formula:

$d_{max} = 2\cdot b$ (2)

If we know that $b = 17$ , then the maximum distance between any two points of the ellipse is:

$d_{max} = 2\cdot (17\,ft)$

$d_{max} = 34\,ft$

The <em>maximum</em> distance between any two points of the ellipse is 34 feet. $\blacksquare$

<h3>Remark</h3>

The statement is incomplete and poorly formatted, correct form is presented below:

<em>An elliptical-shaped path surrounds a garden, modeled by </em> $\frac{(x-20)^{2}}{169} + \frac{(y-18)^{2}}{289} = 1$ <em>, where all measurements are in feet. What is the maximum distance between any two points of the path.</em>