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NikAS [45]
2 years ago
14

What is the equation that passes through the point (3,-6) and has a slope of 3/4?

Mathematics
1 answer:
Vladimir79 [104]2 years ago
3 0

Answer:

lol

Step-by-step explanation:

Some oone idea about this ??

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-4x+7 x= -1 evaluate the expression
NeX [460]
Hello luv! So here is how I will evaluate this expression
-4x+7, x=-1 so you are using substitution
-4(-1)+7
=11

:)

3 0
3 years ago
Suppose you regress the natural log of total family expenditures on household size using observations of households from the 201
postnew [5]

Answer:

Step-by-step explanation:

Please check below in the attached, you will see answer to given questions, thank you, I hope it helps.

4 0
3 years ago
What is the relationship between the number of tickets,n, and the total cost of the tickets, c?
enot [183]

Answer:

Step-by-step explanation:

It c just took the test

7 0
3 years ago
Paige invested 1200 at an interest rate of 5.75% compounded quarterly. Determine the value of her investments in 7 years.
iragen [17]
Use the formula A=p(1+r)^n
where 
A= value of investment
r= rate
n= time period
p= amount invested
in this question 
r= 5.75% but compounded quarterly means divide this by 4
r= 23/1600
n=7*4
n=28
p= $1200
A=1200(1+23/1600)^28

A= $1789.54

Therefore the value of her investment in 7 years is $1789.54
4 0
3 years ago
Evaluate the given integral by changing to polar coordinates. 8xy dA D , where D is the disk with center the origin and radius 9
BabaBlast [244]

Answer:

0

Step-by-step explanation:

∫∫8xydA

converting to polar coordinates, x = rcosθ and y = rsinθ and dA = rdrdθ.

So,

∫∫8xydA = ∫∫8(rcosθ)(rsinθ)rdrdθ = ∫∫8r²(cosθsinθ)rdrdθ = ∫∫8r³(cosθsinθ)drdθ

So we integrate r from 0 to 9 and θ from 0 to 2π.

∫∫8r³(cosθsinθ)drdθ = 8∫[∫r³dr](cosθsinθ)dθ

= 8∫[r⁴/4]₀⁹(cosθsinθ)dθ

= 8∫[9⁴/4 - 0⁴/4](cosθsinθ)dθ

= 8[6561/4]∫(cosθsinθ)dθ

= 13122∫(cosθsinθ)dθ

Since sin2θ = 2sinθcosθ, sinθcosθ = (sin2θ)/2

Substituting this we have

13122∫(cosθsinθ)dθ = 13122∫(1/2)(sin2θ)dθ

= 13122/2[-cos2θ]/2 from 0 to 2π

13122/2[-cos2θ]/2 = 13122/4[-cos2(2π) - cos2(0)]

= -13122/4[cos4π - cos(0)]

= -13122/4[1 - 1]

= -13122/4 × 0

= 0

5 0
2 years ago
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