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vesna_86 [32]
2 years ago
13

Ann and Betty shared a sum of money in the ratio 2:3. If Ann received $120,what was the amount of money shared?

Mathematics
1 answer:
Ivenika [448]2 years ago
4 0

Answer:

$420

Step-by-step explanation:

Given data

GIven ratio=  2:3

The total ratio= 2+5= 7

Ann's share= $120

Let us apply the part to all approach

let the total amount be x

so for Ann

2/7= 120/x

cross multiply

2x= 120*7

2x= 840

divide both sides by 2

x= 840/2

x= 420

Hence the amount shared is $420

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Dora earns an annual salary of $85,608. How much does she earn every month. A.$6,144. B. $7,134. C.$7,144. D. $7,234
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Hi let me help you out there 
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$85,608 is the amount she earns in a year 
you do 
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85,608 divided by 12= $7,134
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Alex wants to fence in an area for a dog park. He has plotted three sides of the fenced area at the points E (1, 5), F (3, 5), a
hram777 [196]

Answer:

(1,1)

Step-by-step explanation:

Given: E, F, G, H denote the three coordinates of the area fenced

To find: coordinates of point H

Solution:

According to distance formula,

length of side joining points (x_1,y_1)\,,\,(x_2,y_2) is equal to \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

So,

EF=\sqrt{(3-1)^2+(5-5)^2}=2\,\,units\\FG=\sqrt{(6-3)^2+(1-5)^2}=\sqrt{9+16}=5\,\,units\\GH=\sqrt{(x-6)^2+(y-1)^2}\\EH=\sqrt{(x-1)^2+(y-5)^2}

Perimeter of a figure is the length of its outline.

EF+FG+GH+EH=16\\2+5+\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16-2-5\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9

Put (x,y)=(1,1)

\sqrt{(1-6)^2+(1-1)^2}+\sqrt{(1-1)^2+(1-5)^2}=9\\\sqrt{25}+\sqrt{16}=9\\5+4=9\\9=9

This is true.

So, the point (1,1) satisfies the equation \sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9

So, point H is (1,1).

7 0
3 years ago
Can someone help me?
Savatey [412]

Answer:

4.5>2.89

Step-by-step explanation:

This question is asking for the comparison between the values of both numbers. 4.5 is greater than 2.89, and this can be written as 4.5>2.89

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