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3 years ago

Actual mechanical advantage and ideal mechanical advantage are not equal. True or False

Physics

1 answer:

alina1380 [7]3 years ago

6 0

It is False because it is not related to the efficiency of a machine

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If you used 650 W of power lifting a 300 N weight in 2 seconds how high did you lift?

dimulka [17.4K]

Answer:

4.33m

Explanation:

Power = work done/ time

work done = power × time =650 × 2 = 1300J

work done = force × distance

distance = work done/force

distance = 1300/300 = 4.33m

7 0

3 years ago

A two-turn circular wire loop of radius 0.63 m lies in a plane perpendicular to a uniform magnetic field of magnitude 0.219 T. I

Basile [38]

Answer:

The magnitude of the average induced emf in the wire during this time is 9.533 V.

Explanation:

Given that,

Radius r= 0.63 m

Magnetic field B= 0.219 T

Time t= 0.0572 s

We need to calculate the average induce emf in the wire during this time

Using formula of induce emf

$E=-\dfrac{d\phi}{dt}$

$E=-B\dfrac{dA}{dt}$

$E=-B\dfrac{A_{2}-A_{1}}{dt}$

$E=B\dfrac{A_{1}-A_{2}}{dt}$ .....(I)

In reshaping of wire, circumstance must remain same.

We calculate the length when wire is in two loops

$l=2\times 2\pi\times r_{1}$

$l=2\times 2\pi\times 0.63$

$l=7.916\ m$

The length when wire is in one loop

$l=2\pi\times r_{2}$

$7.916=2\times \pi\times r_{2}$

$r_{2}=\dfrac{7.916}{2\times \pi}$

$r_{2}=1.259\ m$

We need to calculate the initial area

$A_{1}=N\times\pi\times r_{1}^2$

Put the value into the formula

$A_{1}=2\times3.14\times(0.63)^2$

$A_{1}=2.49\ m^2$

The final area is

$A_{2}=N\times\pi\times r_{2}^2$

$A_{2}=1\times\pi\times(1.259)^2$

$A_{2}=4.98\ m^2$

Put the value of initial area and final area in the equation (I)

$E=0.219\dfrac{2.49-4.98}{0.0572}$

$E=-9.533\ V$

Negative sign shows the direction of induced emf.

Hence, The magnitude of the average induced emf in the wire during this time is 9.533 V.

6 0

3 years ago

A 1500kg car is at rest before it accelerates when the light turns green. If it covers 45.0 meters in 15.0 seconds, what is the

lana [24]

Answer:

300N

Explanation:

Given parameters:

Mass of car = 1500kg

Initial velocity = 0m/s

Distance covered = 45m

Time = 15s

Unknown:

Net force applied = ?

Solution:

From Newton's second law:

Force = mass x acceleration

Force = mass x $\frac{v - u}{t}$

v is the final velocity

u is the initial velocity

t is the time taken

Final velocity = $\frac{45}{15}$ =3m/s

Force = 1500 x $\frac{3 - 0}{15}$ = 300N

8 0

3 years ago

Describe the way the light travels when you see a car behind you in the rear view mirror

GrogVix [38]

Answer:

Described below

Explanation:

When you see a car behind you in the rear view mirror, it means that light rays travelling from the right hand side of the car driver behind are being reflected by the mirror to get to your eyes on the right side of the light rays from the drivers left hand side.

3 0

3 years ago

The contour interval of a topographic map is 25 feet. How many contour lines will be drawn between sea level and an elevation of

Juliette [100K]

<span>If a contour interval of a topographic map is 50 feet, there would be 3 contour lines drawn between sea level and an elevation of 175 feet.</span>

8 0

3 years ago