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Salsk061 [2.6K]
2 years ago
5

You are the science officer on a visit to a distant solar system. Prior to landing on a planet you measure its diameter to be 1.

70×107 m and its rotation period to be 22.3 hours. You have previously determined that the planet orbits 2.70×1011 m from its star with a period of 402 earth days. Once on the surface you find that the free-fall acceleration is 12.5 m/s2 .
A) What is the mass of the planet?
B) What is the mass of the star?
Physics
1 answer:
Arlecino [84]2 years ago
4 0

Answer:

sorry I don't know but you

Explanation:

can ask quora it's an app

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The best and most correct answer among the choices provided by the question is decreases <span>.


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Is dimensionally correct equation must be physically correct . Explain your logic behind physically correct equation ?​​
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1 year ago
If the mass of the material is 50 g in the volume of the material is 9cm^3 what would the density of the material be
Semmy [17]

Density is calculated by dividing the mass by the volume.

D=\frac{m}{v}

Substitute the corresponding values into the equation.

D=\frac{50 g}{9 cm^3}

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7 0
3 years ago
A car tyre is pumped to a pressure of 20000 Nm-2 in the morning when the temperature is 23 oC. Later in the day, the temperature
tekilochka [14]

Answer:

20743.24 Nm¯²

Explanation:

From the question given above, the following data were obtained:

Initial pressure (P1) = 20000 Nm¯²

Initial temperature (T1) = 23 °C

Final temperature (T2) = 34 °C

Final pressure (P2) =?

Volume = constant

Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T1) = 23 °C

Initial temperature (T1) = 23 °C + 273 = 296 K

Final temperature (T2) = 34 °C

Final temperature (T2) = 34 °C + 273 = 307 K

Finally, we shall determine the final (i.e the new) pressure of the tyre.

Initial pressure (P1) = 20000 Nm¯²

Initial temperature (T1) = 296 K

Final temperature (T2) = 307 K

Final pressure (P2) =?

Volume = constant

Since the volume is constant, the final (i.e the new) pressure of the tyre can be obtained by using the following formula:

P1/T1 = P2/T2

20000 / 296 = P2 /307

Cross multiply

296 × P2 = 20000 × 307

Divide both side by 296

P2 = (20000 × 307) /296

P2 = 20743.24 Nm¯²

Therefore, the new pressure of the tyre is 20743.24 Nm¯²

3 0
3 years ago
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