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Salsk061 [2.6K]
2 years ago
5

You are the science officer on a visit to a distant solar system. Prior to landing on a planet you measure its diameter to be 1.

70×107 m and its rotation period to be 22.3 hours. You have previously determined that the planet orbits 2.70×1011 m from its star with a period of 402 earth days. Once on the surface you find that the free-fall acceleration is 12.5 m/s2 .
A) What is the mass of the planet?
B) What is the mass of the star?
Physics
1 answer:
Arlecino [84]2 years ago
4 0

Answer:

sorry I don't know but you

Explanation:

can ask quora it's an app

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Air is cooled in a process with constant pressure of 150 kPa. Before the process begins, air has a specific volume of 0.062 m^3/
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Answer:

The pressure is constant, and it is P = 150kpa.

the specific volumes are:

initial = 0.062 m^3/kg

final = 0.027 m^3/kg.

Then, the specific work can be written as:

W = \int\limits^{vf}_{vi} {Pdv} \, = P(vf - vi) = 150kPa*(0.0027 - 0.062)m^3/kg = -5.25 kPa*m^3/kg.

The fact that the work is negative, means that we need to apply work to the air in order to compress it.

Now, to write it in more common units we have that:

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7 0
3 years ago
A certain car engine delivers enough force to create 630 N⋅m of torque when the engine is operating at 3200 revolutions per minu
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The appropriate expression for the calculation of power by relating the angular energy in a given time.

In other words the instantaneous power of an angular accelerating body is the torque times the angular velocity

P=\tau\omega

Where

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\omega =Angular speed

Our values are given by

\tau = 630Nm

\omega = 3200rev/min

The angular velocity must be transformed into radians per second then

\omega = 3200rev/min (\frac{2\pi rad}{60s})

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Replacing,

P=(630)(335.103)

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Explanation:

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6 0
2 years ago
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