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3 years ago

10. Walter makes a cable payment of $84 each month. Which table

Mathematics

1 answer:

andrew-mc [135]3 years ago

4 0

56=88888 min inshallah and the lions game on the lions game and the lions game on the lions game

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Please help this is due in 10 minutes!!!!!!

Sergio039 [100]

Answer:

Step-by-step explanation:

you just gotta add all the side-lengths together and consider each grid square as 10 instead of 1.

so 70 + 40 + 20 + 60 + 20 + 40 i believe.

this all equals 250.

ask your teacher if its a type, because there's no 250 on there. grab a calculator or something as proof.

3 0

3 years ago

If √3 = 1.73 to 2 dp, find the value of 4/√3 to 2 dp

Mashutka [201]

Answer:2.31

Step-by-step explanation: considering that the root of 3 has already been given. Will just divide 4 by the root of 3 which is 1.73. and the answer it gives is 2.31

3 0

4 years ago

8 divided by 2 (2+2). 1 or 16

laiz [17]

Answer:

Step-by-step explanation:

$8/2(2+2)$

Following the order of operations (PEMDAS), combine the terms in your parentheses:

$8/2(4)$

Remember that we follow the order of operations from left to right.

Divide 8 into 2:

$4(4)$

Multiply:

$16$

8 0

3 years ago

Using your new formula from the previous question ,what is the side length of an equlalertal trangle that has a perimeter of 24.

valina [46]

The perimeter of an equilateral triangle is just 3s as all the sides are, well, equal :) so

P=3s and we are told that P=24.6 so

3s=24.6

s=8.2 cm

7 0

3 years ago

We are standing on the top of a 320 foot tall building and launch a small object upward. The object's vertical altitude, measure

STALIN [3.7K]

Answer:

The highest altitude that the object reaches is 576 feet.

Step-by-step explanation:

The maximum altitude reached by the object can be found by using the first and second derivatives of the given function. (First and Second Derivative Tests). Let be $h(t) = -16\cdot t^{2} + 128\cdot t + 320$ , the first and second derivatives are, respectively:

First Derivative

$h'(t) = -32\cdot t +128$

Second Derivative

$h''(t) = -32$

Then, the First and Second Derivative Test can be performed as follows. Let equalize the first derivative to zero and solve the resultant expression:

$-32\cdot t +128 = 0$

$t = \frac{128}{32}\,s$

$t = 4\,s$ (Critical value)

The second derivative of the second-order polynomial presented above is a constant function and a negative number, which means that critical values leads to an absolute maximum, that is, the highest altitude reached by the object. Then, let is evaluate the function at the critical value:

$h(4\,s) = -16\cdot (4\,s)^{2}+128\cdot (4\,s) +320$

$h(4\,s) = 576\,ft$

The highest altitude that the object reaches is 576 feet.

6 0

4 years ago