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EleoNora [17]
3 years ago
7

Anthony is standing on the top of a building 10 m high holding a 7 kg bowling ball. Mildred dug a 2-m-deep hole next to the base

of the building. What is the gravitational potential energy of the bowling ball relative to the bottom of the hole? P.E = mgh
A. 137.2 J
B. 548.8 J
C. 686.0 J
D. 823.2 J
Physics
1 answer:
Leokris [45]3 years ago
8 0

Answer:

B

Explanation:

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<h3>How to solve for the normal force</h3>

The normal force is calculated using the work energy principle which is applied as below

K₁ + U₁ = K₂

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the subscripts 1,2 , and 3 = a, b, and c

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at C

for normal force to be zero

ma = mg

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v²₃ = gR

and v²₃ = 2g(h - R)

gR = 2gh - 2gR

gR + 2gR = 2gh

3gR = 2gh

3R/2 = h

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