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Lostsunrise [7]
3 years ago
13

A ball is launched horizontally from the top of a cliff with an initial velocity of 20 m/s. If the ball strikes the ground after

five seconds, then (a) how high was the cliff and (b) how far from the base of the cliff will the ball land?
Physics
1 answer:
stich3 [128]3 years ago
6 0

Answer: you are the imposter you killed red then vented in admin

Explanation:

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No, the car will not make it to the top of the hill.

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Let ΔX be how long the slope of the hill is, Δx be how far the car will travel along the slope of the hill, Ф be the angle the slope of the hill makes with the horizontal(bottom of the hill), ki be the kinetic energy of the car at the bottom of the hill and vi be the velocity of the car at the bottom of the hill and kf be the kinetic energy of the car when it stop moving at vf.

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W = (kf - ki)

Since the car will come to a stop, kf = 0 J

W = -ki

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(Note that the maximum angle Ф is 90° because the slope of a hill can never be greater ≥ 90° because that would then mean the car cannot travel uphill.)

Since the car can never travel the distance of the slope, it can never make it to the top of the hill.

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