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Lostsunrise [7]

2 years ago

13

A ball is launched horizontally from the top of a cliff with an initial velocity of 20 m/s. If the ball strikes the ground after

five seconds, then (a) how high was the cliff and (b) how far from the base of the cliff will the ball land?

1 answer:

stich3 [128]2 years ago

6 0

Answer: you are the imposter you killed red then vented in admin

Explanation:

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Two objects, A and B, are in contact with one another. Initially, the temperature of A is 50 °C and the temperature of B is 100

V125BC [204]

Answer:

B

Explanation:

because kinetic energy is directly proportional to temperature so the hottor the object, the more kinetic energy.

6 0

2 years ago

The nuclei of large atoms, such as uranium, with 9292 protons, can be modeled as spherically symmetric spheres of charge. The ra

Scrat [10]

Answer:

Part 1 $E = 2.42 * 10^{21} N/C$

Part 2 $E = 1.3 * 10^{13} N/C$

Part 3 $E = 0$

Explanation:

Given

Number of protons $= 92$

Radius of nucleus $r_n = 7.4 * 10^{-15} m$

Distance of the electrons $r_1 = 1.0 * 10^ {-10} m$

Part 1

Electric field produced by just outside its surface

$E = \frac{q}{4\pi*E_0* r_n^2 } \\E = \frac{9 * 10^ 9 * 92 * 1.6 * 10^{-19}}{(7.4* 10^{-15})^2} \\E = 2.42 * 10^{21} N/C$

Part 2

Electric field produced by just outside its surface

$E = \frac{q}{4\pi*E_0* r_n^2 } \\E = \frac{9 * 10^ 9 * 92 * 1.6 * 10^{-19}}{(1* 10^{-15})^2} \\E = 1.3 * 10^{13} N/C$

Part 3

The net electric field inside a uniform shell of negative charge is zero because the electric flux lines cancel out each other

hence, the solution is

Part 1 $E = 2.42 * 10^{21} N/C$

Part 2 $E = 1.3 * 10^{13} N/C$

Part 3 $E = 0$

7 0

2 years ago

Question 2 of 10

tangare [24]

Explanation:

everything can be found in the picture

8 0

2 years ago

Describe mechanical energy in your own words

Vlad [161]

Answer:

motion......

movement.....

3 0

2 years ago

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An eagle flew for 3 hours at 115 km/h and 5 hours at 136 km/h. How far did the eagle fly?

Yanka [14]

Answer:

the eagle flew 1,025 km

Explanation:

since the eagle flew for 3 hours at 115 km/h it flew a total of 345 km during that time. During the 5 hours at 136 km/h the eagle flew a total of 680 km.

3 0

2 years ago