All categories

3 years ago

Which of these is emitted during beta decay ?

Physics

2 answers:

satela [25.4K]3 years ago

4 0

Answer:

C. a small charged particle.

Explanation:

typically beta radiation emits an electron which is a small negativity charged particle.

hope it helps. :)

Vesna [10]3 years ago

3 0

Answer:

C) a small charged particle

Explanation:

AP3X

You might be interested in

A person on a bike (m=90kg) is traveling 4m/s at the top of a 2m hill. What is his/her kinetic energy?

guajiro [1.7K]

Answer:

Ek = 720J

Explanation:

Ek = 0.5mv^2

Ek = 0.5(90)(4)^2

Ek = 720J

6 0

3 years ago

Read 2 more answers

PLEASE HELP ME: as the sun ages and loses mass, what do you think will happen to the outer planets?

irakobra [83]

Answer:

based on theory, its gravitational pull on the other planets will weaken and they'll drift farther away.

4 0

3 years ago

(a) If a proton with a kinetic energy of 6.2 MeV is traveling in a particle accelerator in a circular orbit with a radius of 0.5

Tju [1.3M]

Answer:

The fraction of its energy that it radiates every second is $3.02\times10^{-11}$ .

Explanation:

Suppose Electromagnetic radiation is emitted by accelerating charges. The rate at which energy is emitted from an accelerating charge that has charge q and acceleration a is given by

$\dfrac{dE}{dt}=\dfrac{q^2a^2}{6\pi\epsilon_{0}c^3}$

Given that,

Kinetic energy = 6.2 MeV

Radius = 0.500 m

We need to calculate the acceleration

Using formula of acceleration

$a=\dfrac{v^2}{r}$

Put the value into the formula

$a=\dfrac{\dfrac{1}{2}mv^2}{\dfrac{1}{2}mr}$

Put the value into the formula

$a=\dfrac{6.2\times10^{6}\times1.6\times10^{-19}}{\dfrac{1}{2}\times1.67\times10^{-27}\times0.51}$

$a=2.32\times10^{15}\ m/s^2$

We need to calculate the rate at which it emits energy because of its acceleration is

$\dfrac{dE}{dt}=\dfrac{q^2a^2}{6\pi\epsilon_{0}c^3}$

Put the value into the formula

$\dfrac{dE}{dt}=\dfrac{(1.6\times10^{-19})^2\times(2.3\times10^{15})^2}{6\pi\times8.85\times10^{-12}\times(3\times10^{8})^3}$

$\dfrac{dE}{dt}=3.00\times10^{-23}\ J/s$

The energy in ev/s

$\dfrac{dE}{dt}=\dfrac{3.00\times10^{-23}}{1.6\times10^{-19}}\ J/s$

$\dfrac{dE}{dt}=1.875\times10^{-4}\ ev/s$

We need to calculate the fraction of its energy that it radiates every second

$\dfrac{\dfrac{dE}{dt}}{E}=\dfrac{1.875\times10^{-4}}{6.2\times10^{6}}$

$\dfrac{\dfrac{dE}{dt}}{E}=3.02\times10^{-11}$

Hence, The fraction of its energy that it radiates every second is $3.02\times10^{-11}$ .

5 0

3 years ago

Which property do metalloids share with nonmetals? Both are gases at room temperature. Both can react to form acidic compounds.

CaHeK987 [17]

The property that metalloids share with nonmetals are

Both can react to form acidic compounds

8 0

4 years ago

Read 2 more answers

Be sure to show all 4 steps for each of the problems below.

Kisachek [45]

Answer:

1=920

2=2300

Explanation:

from the question,

M¹=23

H¹=4

g=10(constant)

using the formula

P. E,= mgh

P. E= 23×10×4=920

P. E=23×10×10=2300

7 0

4 years ago