Graph the function y = x3 + 6x2 + 2x – 11. Based on the graph, what is the largest possible x-value if y = 0?

Mathematics

2 answers:

professor190 [17]2 years ago

5 0

Answer:

Step-by-step explanation:

The graph is done using Desmos. Just by substitution x = 1 will force the graph to go to y = 0, but graphs are not always that good. This one gets 1.111

to get y = 0. I'd use 1 if you had to answer it and a computer will mark it.

Tanya [424]2 years ago

4 0

Answer:

1.11 is correct, just took the test and passed with 100%

Step-by-step explanation:

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Algebra 1: Factoring Polynomials Factor the common factor out of each expression: 40n^4m^2+40n^3m^3-32n^3

Nina [5.8K]

Taking out the greatest common factor

GCF of 40, 40 and 32 = 8
GCF of n^4, n^3 and n^3 is n^3

so the factors are

8n^3(5nm^2 +5m^3 - 4)

7 0

3 years ago

Ignore circled one and work it out please

mash [69]

Answer:

a. $\frac{(x-7)}{x^2+x-30}$

Step-by-step explanation:

$\huge \frac{x^2-3x-28}{(x^2+10x+24)(x-5)} \\\\\huge {=\frac{x^2-7x+4x-28}{(x^2+6x+4x+24)(x-5)}}\\\\\huge {=\frac{x(x-7)+4(x-7)}{\{x(x+6)+4(x+6)\}(x-5)}}\\\\\huge {=\frac{(x-7)(x+4)}{(x+6)(x+4)(x-5)}}\\\\\huge {=\frac{(x-7)}{(x+6)(x-5)}}\\\\\huge {=\frac{(x-7)}{x^2+(6-5)x+6(-5)}}\\\\\huge {=\frac{(x-7)}{x^2+x-30}}$