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cupoosta [38]
3 years ago
9

Differentiate between nuclear charge and effective nuclear charge​

Chemistry
1 answer:
ipn [44]3 years ago
3 0

hope it helps ..............

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If I have one mole of sulfur, how many atoms would that be?
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Atoms of sulfur = 9.60⋅g32.06⋅g⋅mol−1×6.022×1023⋅mol−1

Explanation:

because the units all cancel out, the answer is clearly a number, ≅2×1023 as required.

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When a planet has the illusion of moving backwards or bouncing up and down it is exhibiting what?
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What volume of o2 is needed to react fully with 720. Ml of nh3
Galina-37 [17]

Ammonia undergoes combustion with oxygen to produce nitric oxide and water. The volume of the oxygen required to react with 720 ml of ammonia is 900 ml.

<h3>What is volume?</h3>

Volume is the area occupied by the substance and is the ratio of the mass to the density.

At STP, 1 mole of gas occupies 22.4 L of volume

Given,

Volume of ammonia reacted = 0.720 L

The combustion reaction is shown as,

\rm 4NH_{3} + 5O_{2} \rightarrow 4NO +6H_{2}O

From the stoichiometry of the reaction, it can be said that,

(4 \times  22.4) L of ammonia reacts with (5 \times  22.4) L of oxygen gas.

So, 0.720 L of  ammonia will react with:

\dfrac{ (5 \times  22.4)}{(4 \times  22.4)} \times 0.720 = 0.9 \;\rm L

Therefore, the volume of oxygen required is 900 mL.

Learn more about volume here:

brainly.com/question/14090111

#SPJ4

6 0
2 years ago
What organelles are involved in the production of proteins
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Read 2 more answers
Argon has a pressure of 34.6 atm. It is transferred to a new tank with a volume of 456 L and pressure of 2.94 atm. What was the
NemiM [27]

Answer:

38.75 L

Explanation:

From the question,

Applying Boyles Law,

PV = P'V'....................... Equation 1

Where P = Original pressure of the Argon gas, V = Original Volume of Argon gas, P' = Final pressure of Argon gas, V' =  Final Volume of Argon gas.

make V the subject of the equation

V = P'V'/P.................... Equation 2

Given: P = 34.6 atm, V' = 456 L, P' = 2.94 atm.

Substitute these values into equation 2

V = (456×2.94)/34.6

V = 38.75 L

3 0
3 years ago
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