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xz_007 [3.2K]
3 years ago
11

A human lung at maximum capacity has a volume of 3.0 liters. If the partial pressure of oxygen in the air is 21.1 kilopascals an

d the air temperature is 295 K, how many moles of oxygen are in the lung?
Chemistry
1 answer:
Juliette [100K]3 years ago
4 0

V = maximum capacity of human lung = 3 liter = 3 x 0.001 m³ = 0.003 m³      (Since 1 liter = 0.001 m³)

P = pressure of oxygen = 21.1 kilo pascal = 21.1 x 1000 = 21100 Pa      (since 1 kilo = 1000)

T = temperature of air = 295 K

n = number of moles of oxygen

Using the ideal gas equation

PV = n RT

inserting the above values in the equation

(21100) (0.003) = n (8.314) (295)

n = 0.026 moles



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