1:) <span>Zn + 2 HCl = ZnCl2 + H<span>2
</span></span>2:) 4 Fe + 3 O2 = 2 Fe2O3
The circulatory system<span> also transports oxygen from the </span>lungs<span> to the cells. Now the cells have what they need for </span>cellular respiration<span>: oxygen and glucose. The teamwork doesn't end there, however. The </span>circulatory system<span> also transports carbon dioxide waste from the cells to the </span>lungs<span> of the </span>respiratory system<span>.</span>
Explanation:
carbon dioxide waste from the body, is a result of
cellular metabolism. Through exhalation, a body gets rid of CO2. (the lungs), are most important in removal of co2.
10) cellular transport through the lungs.
11) o2 (inhalation) lungs, oxygenate cells to deliver o2 through the bloodstream to perform proper function. plus the pulmonary arteries renew and release CO2 from the body..
Answer:
Explanation:To convert from cal/(g*C) to J/(kg*K), we just need to find a conversion factor for specific heat. There is really no mathematical way to do this other than to look in a physics or chemistry book and find a conversion factor. After doing this, you will see that 1 cal/(g*C) is equal to 4,186 J/(kg*K).
To find the specific heat of a material, first look at the units. There is energy per unit mass per unit temperature. So if we are given an amount of energy appllied to an object, its mass and how much the temperature of the object rises, we can calculate its specifc heat by dividing the energy by both the mass and the temperature, but don't forget to keep the units as they are:
Specific heat of the metal = (95 cal)/(10 K * 700g) = 0.014 cal/(g*K)
To find how much energy it requires to melt 250 grams of ice, we will need what is called the Latent Heat of Melting for ice. This is the amount of heat required to change unit mass of a solid into unit mass of a liquid at a constant temperature. Again, using a reference, the latent heat of melting for ice is found to be 334 kJ/kg. So the energy required to melt one kg of ice is 334 kJ. The amount of energy required to melt 0.250 kg of ice is then:
334 * 0.250 = 83.5 kJ
