91 grams of sodium azide required to decompose and produce 2.104 moles of nitrogen.
Explanation:
2NaN3======2Na+3N2
This is the balanced equation for the decomposition and production of sodium azide required to produce nitrogen.
From the equation:
2 moles of NaNO3 will undergo decomposition to produce 3 moles of nitrogen.
In the question moles of nitrogen produced is given as 2.104 moles
so,
From the stoichiometry,
3N2/2NaN3=2.104/x
= 3/2=2.104/x
3x= 2*2.104
= 1.4 moles
So, 1.4 moles of sodium azide will be required to decompose to produce 2.104 moles of nitrogen.
From the formula
no of moles=mass/atomic mass
mass=no of moles*atomic mass
1.4*65
= 91 grams of sodium azide required to decompose and produce 2.104 moles of nitrogen.
Answer:
The elements in the periodic table are arranged in order of increasing atomic number.
Explanation:
Answer:
the first one is the answer
Answer is: in this experiment it is best to use some liquid alkanes (for example hexane), because gasoline<span> consists of hydrocarbons with between four and twenty carbon atoms</span>. Gasoline is a mixture <span> of many different hydrocarbons: </span><span>alkanes (paraffins), cycloalkanes and alkenes (olefins).</span>
Answer:
the answer is b ch2 ch ch3 cl ch2 ch2 ch3
