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alekssr [168]
3 years ago
15

Help with science----?????///

Chemistry
1 answer:
N76 [4]3 years ago
8 0

Answer + Explanation:

1. The different ways tectonic plates move in relation to each other are:

        convergent (where plates move into one another)  

        divergent (where plates move apart)

        transform (where plates move sideways in relation to each other)

2. Convergent plate boundaries can result in:

       earthquakes, volcanoes, and the formation of mountains.

The Himalaya Mountains are the result of convergent plate boundaries.

3. Landforms that are a result of divergent boundaries are rift valleys and mid-oceanic ridges.

        Locations where this occurs are:  Mid-Atlantic Ridge, Red Sea Rift, Baikal Rift Zone

, East African Rift, East Pacific Rise,  Gakkel Ridge, Galapagos Rise, and Explorer Ridge.

4. Transforming plate boundaries results in shallow earthquakes, large lateral displacement of rock, and a broad zone of crustal deformation.

  A location where this occurs is: San Andreas Fault in western California

<em>sorry that's all I can help you with today :/ if I have more time I'll answer the other questions!! If I helped you please don't forget to mark me brainliest!!</em>

- sophi

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The second on, A man who works as a computer programmer and sits at desk magority of the day.

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Silver chloride, AgCl (Ksp = 1.8 x 10‒10), can be dissolved in solutions containing ammonia due to the formation of the soluble
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Explanation:

The given reaction will be as follows.

           AgCl(s) \rightarrow Ag^{+}(aq) + Cl^{-}(aq) ............. (1)

     K_{sp} = [Ag^{+}][Cl^{-}] = 1.8 \times 10^{-10}

Reaction for the complex formation is as follows.

          Ag^{+}(aq) + 2NH_{3}(aq) \rightleftharpoons [Ag(NH_{3})_{2}]^{+}(aq) ........... (2)

          K_{f} = \frac{[Ag(NH_{3})_{2}]}{[Ag^{+}][NH_{3}]^{2}} = 1.0 \times 10^{8}

When we add both equations (1) and (2) then the resultant equation is as follows.

             AgCl(s) + 2NH_{3}(aq) \rightarrow [Ag(NH_{3})_{2}]^{+}(aq) + Cl^{-}(aq) ............. (3)

Therefore, equilibrium constant will be as follows.

                       K = K_{f} \times K_{sp}

                          = 1.0 \times 10^{8} \times 1.8 \times 10^{-10}

                          = 1.8 \times 10^{-2}

Since, we need 0.010 mol of AgCl to be soluble in 1 liter of solution after after addition of NH_{3} for complexation. This means we have to set

               [Ag^{+}] = [Cl^{-}]

                          = \frac{0.010 mol}{1 L}

                          = 0.010 M

For the net reaction, AgCl(s) + 2NH_{3}(aq) \rightarrow [Ag(NH_{3})_{2}]^{+}(aq) + Cl^{-}(aq)

Initial :                             0.010         x                     0                           0

Change :                    -0.010         -0.020             +0.010                +0.010

Equilibrium :                   0            x - 0.020           0.010                 0.010

Hence, the equilibrium constant expression for this is as follows.

              K = \frac{[Ag(NH_{3})^{+}_{2}][Cl^{-}]}{[NH_{3}]^{2}}

     1.8 \times 10^{-2} = \frac{0.010 \times 0.010}{(x - 0.020)^{2}}

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or,          x = 0.095 mol (approx)

Thus, we can conclude that the number of moles of NH_{3} needed to be added is 0.095 mol.

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