Answer:
- <u><em>Option A.) 2 ppm</em></u>
Explanation:
<u><em>60 particles in 30 million</em></u> can be expressed as a fraction:
And, dividing both numerator and denominator by 30, that can be simplified as:
That means 2 particles of sulfur dioxide in 1 million particles of sample, which is 2 parts per million or<u> 2 ppm</u>, which is the option A.
Answer:
1
Explanation:
there is only one sulphur (S) atoms in the formula for sodium sulphate
1.194 mol
(remember to use sig figs!)
Answer:
CaCl₂
Step-by-step explanation:
The <em>empirical formula</em> is the simplest whole-number ratio of atoms in a compound.
The ratio of atoms is the same as the ratio of moles.
So, our job is to calculate the molar ratio of Ca to Cl.
Data:
Mass of Ca = 3.611 g
Mass of Cl = 6.389 g
Calculations
Step 1. <em>Calculate the moles of each element
</em>
Moles of Ca = 3.611 g Ca × (1 mol Ca/(40.08 g Ca)= 0.090 10 mol Ca
Moles of Cl = 6.389 g Cl
Step 2. <em>Calculate the molar ratio of the elements
</em>
Divide each number by the smallest number of moles
Ca:Cl = 0.090 10:0.1802 = 1:2.000
Step 3. Round the molar ratios to the nearest integer
Ca:Cl = 1:2.000 ≈ 1:2
Step 4: <em>Write the empirical formula
</em>
EF = CaCl₂
Zn is the most active of the three metals.
