Answer:
Given : EFGH is a Parallelogram
Prove : EG Bisects HF , HF Bisects EG
Step-by-step explanation:
Proof
Check image below
The answer would be B, because 12.80 times .15 is 1.92
Answer:
Part 1) The length of the longest side of ∆ABC is 4 units
Part 2) The ratio of the area of ∆ABC to the area of ∆DEF is 
Step-by-step explanation:
Part 1) Find the length of the longest side of ∆ABC
we know that
If two figures are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor
The ratio of its perimeters is equal to the scale factor
Let
z ----> the scale factor
x ----> the length of the longest side of ∆ABC
y ----> the length of the longest side of ∆DEF
so

we have


substitute

solve for x


therefore
The length of the longest side of ∆ABC is 4 units
Part 2) Find the ratio of the area of ∆ABC to the area of ∆DEF
we know that
If two figures are similar, then the ratio of its areas is equal to the scale factor squared
Let
z ----> the scale factor
x ----> the area of ∆ABC
y ----> the area of ∆DEF

we have

so


therefore
The ratio of the area of ∆ABC to the area of ∆DEF is 
The age of Blain is 23 years old
<h3><u>Solution:</u></h3>
Let the age of Blain be "a" and age of Jillian be "b"
Given that Blain is two years older than three times Jillians age
So we can frame a equation as:
age of blain = 2 + 3(age of Jillian)
a = 2 + 3b ----- eqn 1
Also given that Jillian is also 16 years younger than Blain
Age of Jillain = Age of Blain - 16
b = a - 16 ---- eqn 2
Substitute eqn 2 in eqn 1
a = 2 + 3(a - 16)
a = 2 + 3a - 48
a - 3a = -46
-2a = -46
a = 23
Thus the age of Blain is 23 years old