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3 years ago

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Can you name the angle pairs and type the correct code? Please remember to type in ALL CAPS with no spaces.

1 answer:

Anarel [89]3 years ago

4 0

JEANNNNNNMNNNNNNNNNNNNNN

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Solve the following inequality then place the correct answer in the box provided 8x-1<15

Lerok [7]

$8x - 1 < 15 \\ 8x < 15 + 1 \\ 8x < 16 \\ x < \frac{16}{8} \\ x < 2$

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2 years ago

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Solve the system of equations.<br> 2x-15y=6<br> x-6y=-1

Irina18 [472]

Answer:

I don't really have an answer for you but if you need help to get your answer use an app called Cymath it can help with your problems i've used this app a lot of times for this kind of math :)

Step-by-step explanation:

Hope i helped!!

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3 years ago

Which of the following angles is coterminal with one that measures 98 degrees

polet [3.4K]

Answer:

See below

Step-by-step explanation:

You have not provided the options.

But I will explain how you can work it.

Coterminal angles are two or more angles that have the same terminal side in standard.

If you want to find an angle that is coterminal with 98°, you keep adding or subtracting 360°.

$98 + 360 = 458 \\ 98 + 2 \times 360 = 818$

$98 - 360 = - 262$

Therefore 488°, 818°, -262° are examples of angles that are coterminal with 98°

6 0

3 years ago

Write the equation of the quadratic function that passes through the points (-1, 1), (1, 5), and (2,10).

Serjik [45]

Answer:

$\displaystyle f(x)=x^2+2x+2$

Step-by-step explanation:

<u>System Of Linear Equations </u>

In this problem, we'll need to solve a 3x3 system of linear equations because we have three unknowns and three conditions.

We are required to find the equation of the quadratic function that passes through the points (-1, 1), (1, 5), and (2,10)

The general quadratic function can be written as

$\displaystyle f(x)=ax^2+bx+c$

We need to find the values of a,b, and c. Let's use the first condition, i.e. f(-1)=1

$\displaystyle f(-1)=a(-1)^2+b(-1)+c$

$\displaystyle f(-1)=a-b+c$

$\displaystyle a-b+c=1.....[eq\ 1]$

Now we use the second condition f(1)=5

$\displaystyle f(1)=a(1)^2+b(1)+c$

$\displaystyle f(1)=a+b+c$

$\displaystyle a+b+c=5.......[eq\ 2]$

Finally, we use the third condition f(2)=10

$\displaystyle f(2)=a(2)^2+b(2)+c$

$\displaystyle f(2)=4a+2b+c$

$\displaystyle 4a+2b+c=10....[eq\ 3]$

We put together eq 1, eq 2, and eq 3 to form the system

$\displaystyle \left\{\begin{matrix}a-b+c=1\\ a+b+c=5\\ 4a+2b+c=10\end{matrix}\right.$

Adding the first two equations we have

$\displaystyle 2a+2c=6$

$\displaystyle a+c=3$

And also

$\displaystyle b=2$

Using the above equation and the value of b in the third equation, we have

$\displaystyle \left\{\begin{matrix}a+c=3\\ 4a+c=6\end{matrix}\right.$

Subtracting the first equation from the second

$\displaystyle 3a=3$

$\displaystyle a=1$

And therefore

$\displaystyle c=2$

Now we have all the values, the quadratic function is

$\displaystyle \boxed{f(x)=x^2+2x+2}$

6 0

3 years ago

Those are the answer choices! ^

dybincka [34]

Answer:

I think its c bc (PEMDAS) shoes multiplication comes first

7 0

3 years ago

Read 2 more answers