BD bisects LABC. Solve for x and find m2ABC. m_ABD = 4x-2, mZCBD=2x + 6
1 answer:
Answer:
i) x = 4°
ii) <ABC = 28°
Step-by-step explanation:
Given that BD bisects <ABC then it is true to say that;
Angle m < ABD=m < CBD
Hence;
4x-2 = 2x +6
4x-2x = 6 +2
2x = 8
x=8/2 = 4
x= 4°
Hence
Angle m< ABD = 4x-2 = 4*4 -2 = 16-2 =14°
Angle m < ABC = 2* 14° = 28°
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-(3x-2)=-4(x+1)-4
-3x+2=-4x-4-4
-3x+4x=-4-4-2
x=-10
Answer:4200
Step-by-step explanation:
Answer:
-3, 1, 5, 9
Step-by-step explanation:
2(2) - 7 = -3
2(4) - 7 = 1
2(6) - 7 = 5
2(8) - 7 = 9
The measure of arc LM is 116
The measure angle MBL is 58
The measure of angle MNL is 64
For cylinder
d=10m
So r=5m
h=5m
volume=pi×r^2×h
=3.14×5×5×5
=3.14×125
=392.5m^3
So option a is correct.
