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2 years ago

Can y’all help me find the answer of this math question plz thx

Mathematics

2 answers:

Rufina [12.5K]2 years ago

8 0

.50 because if there’s 8 total and 4 are yellow and half is 4

butalik [34]2 years ago

4 0

Answer:

.50

half the blocks are Yellow, so there is a 50% chance of drawing a yellow block.

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Which of the following statements are true of the graph of the function f(x)=(x+5)(x-3)?

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3 years ago

to support a tree damaged in a storm, a 12-foot wire is secured from the ground to the tree at a point 10 feet off the ground. t

Leokris [45]

Choice given:
33.6°
39.8°
50.2°
56.4°

I drew the figure.
I got 12 ft as the hypotenuse, 10 ft as the opposite.

SinΘ = opposite / hypotenuse
SinΘ = 10/12
SinΘ = 0.83

I used the calculator to get the value of each angle using the sine function
sin(33.6°) = 0.55
sin(39.8°) = 0.64
sin(50.2°) = 0.77
sin(56.4°) = 0.83

The angle where the wire meets the ground is approximately 56.4°

8 0

3 years ago

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Which angles are alternate interior angles?

Sergio [31]

Angles JKH and IHK are alternate interior angles

8 0

2 years ago

What is the initial value of the equation y-3=-7x ?

Ludmilka [50]

The value is 21 Because three represents those to variables which both equal to 21.

6 0

2 years ago

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Situation:

Gala2k [10]

Answer:

5.5 days (nearest tenth)

Step-by-step explanation:

Given formula:

$\sf N=N_0e^{-kt}$

$\sf N_0$ = initial mass (at time t=0)
N = mass (at time t)
k = a positive constant
t = time (in days)

Given values:

$\sf N_0$ = 11 g
k = 0.125

Half-life: The time required for a quantity to reduce to half of its initial value.

To find the time it takes (in days) for the substance to reduce to half of its initial value, substitute the given values into the formula and set N to half of the initial mass, then solve for t:

$\begin{aligned}\sf N & = \sf N_0e^{-kt}\\\\\implies \sf \dfrac{11}{2} & = \sf 11e^{-0.125t}\\\\\sf \dfrac{1}{2} & = \sf e^{-0.125t}\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf \ln e^{-0.125t\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf -0.125t \ln e\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf -0.125t(1)\\\sf t & = \sf \dfrac{\ln \left(\dfrac{1}{2}\right)}{-0.125}\\\\\sf t & = \sf 5.545177444...\\\\\sf t & = \sf 5.5\:\:days\:\:(nearest\:tenth)\end{aligned}$

Therefore, the substance's half-life is 5.5 days (nearest tenth).

Learn more about solving exponential equations here:

brainly.com/question/28016999

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2 years ago

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