39/78 = .5 = 50%
...................
If you factor the denominator of the left multiplicand...
[(a-4)(a+3)]/[a(a-4)] you can see that the (a-4)s cancel out leaving:
(a+3)/a
now you have
(a+3)/a * 2a^3/((a+3)(a-1)) so the (a+3)s cancel out leaving:
1/a * 2a^3/(a-1) which is:
2a^3/(a(a-1)) so now a^1 cancel leaving
2a^2/(a-1)
what is the shading
Step-by-step explanation:
???????
Ok so I think I'm correct
1st number a acute angles
2nd 6
Answer:
<h3>B. -84</h3>
Step-by-step explanation:
Taking the determinant of the matrices we will have;
= 4x(5y) - 2x(3y)
= 20xy - 6xy
= 14xy
Given x = -2 and y = 3
Determinant = 14(-2)(3)
Determinant = -28*3
Determinant = -84
