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Schach [20]
2 years ago
14

Please help i really need it

Mathematics
2 answers:
Alchen [17]2 years ago
6 0
The answer is A because your changing the y- axis
kakasveta [241]2 years ago
4 0

Answer:

b

Step-by-step explanation:

i did that one in class it was right.

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A quadrilateral has congruent diagonals. It is probably a( n) ______.
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7 0
3 years ago
Can someone see if these are right?
qwelly [4]
I didn't get the same answers.

In this problem, 25 is your constant (the number of baby hats you already started out with).
26 will be affected by your variable, d, the number of days. With each day that passes, 26 more hats will be knit, so the expression 26d can be used. 

Set h equal to the constant + hats made per day to create an expression that you can use to solve for h:
h = 26d + 25

Now, just plug the numbers in for d to get h:
When d = 2, h = 26d + 25 = 26(2) + 25 = 77
When d = 4, h = 26d + 25 = 26(4) + 25 = 129
When d = 7, h = 26d + 25 = 26(7) + 25 = 207
When d = 9, h = 26d + 25 = 26(9) + 25 = 259

Your answers should be:
77
129
207
259
5 0
3 years ago
Use a net to find the surface area of the prism.
lawyer [7]
The surface area of the prism will be given by:
SA=2(L×W)+2(L×H)+2(H×W)
SA=2(12×5)+2(12×9)+2(5×9)
SA=120+216+90
SA=426m²

Answer: 426m²
5 0
3 years ago
sorry again for asking this but can someone explain this and give me the answer. Been having a hard time learning this.
Rudik [331]

<em>Hey</em><em>!</em><em>!</em><em>!</em>

<em>In</em><em> </em><em>ques</em><em>tion</em><em> </em><em>no</em><em>.</em><em>4</em><em>,</em><em> </em><em>we</em><em> </em><em>have</em><em> </em><em>to </em><em><u>subtract</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>equation</u></em><em><u>.</u></em>

<em>In</em><em> </em><em>ques</em><em>tion</em><em> </em><em>no</em><em>.</em><em>5</em><em> </em><em>we</em><em> </em><em>have</em><em> </em><em>to</em><em><u> </u></em><em><u>add</u></em><em><u> </u></em><em><u>the </u></em><em><u>equation</u></em><em><u>.</u></em>

<em>Hope </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em>

<h3><em><u>Have</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>great</u></em><em><u> </u></em><em><u>day</u></em></h3>
3 0
3 years ago
Need help in number 12 and 13 PLEASEE!! I don’t get it and I start school the day after tomorrow
Natasha_Volkova [10]

Answer:

The explanations for the graphs are provided down below. Please let me know if you have any questions about my answer.

12 and 13 as written on the worksheet is right.

Step-by-step explanation:

12) The answer given is correct.

The relation between x and y is given as:

y=\frac{x^2}{2}-3 with x \in \{-4,-2,0,2}.

I replaced the word domain with x since the domain is the set of x's for which the relation exists.

We are going to replace x with each of the x's given to see what y corresponds to each.

Let's begin with x=-4.

y=\frac{x^2}{2}-3 with x=-4:

y=\frac{(-4)^2}{2}-3

y=\frac{16}{2}-3

y=8-3

y=5.

So (-4,5) is an ordered pair that should be on our graph.

To find this point you move left 4 from origin then up 5. Now you put a dot where you have landed. Your graph does show this point.

Moving on.

Let's do the next x: x=-2.

y=\frac{x^2}{2}-3 with x=-2:

y=\frac{(-2)^2}{2}-3

y=\frac{4}{2}-3

y=2-3

y=-1.

So (-2,-1) is an ordered pair that should be on our graph.

To find this point you move left 2 from origin and then down 1.  Now you put a dot where you have landed. Your graph shows this point as well.

Now x=0.

y=\frac{x^2}{2}-3 with x=0:

y=\frac{0^2}{2}-3

y=\frac{0}{2}-3

y=0-3

y=-3

So (0,-3) is an ordered pair that should be on our graph.

To find this point you move left and right none and down 3.  Now you put a dot where you have landed. Your graph shows this point.

Now the last point will be at x=2.

y=\frac{x^2}{2}-3 with x=2

y=\frac{2^2}{2}-3

y=\frac{4}{2}-3

y=2-3

y=-1.

So (2,-1) is an ordered pair that should be on our graph.

To find this point you move 2 units right from the origin and then down 1 unit. Now put a dot where you landed.  The graph shows this point as well.

13) The answer given is correct.

g(x)=|x| is the parent function and makes like a V shaped graph where it's vertex is at (0,0).

If we want to move this graph right 3 it becomes:

m(x)=|x-3| \text{ or } m(x)=|(-1)(-x+3)|=|-1||-x+3|=1|-x+3|=|-x+3|=|3-x|.

If you move that up once it becomes:

n(x)=|x-3|+1 or n(x)=|3-x|+1 which is the curve given.

If you don't know about transformations you can choose a few points to plug in to see what's going on with the graph.

Let's choose x=-5,-3,-1,0,1,3,5.

x=-5

f(-5)=|3--5|+1=|3+5|+1=|8|+1=8+1=9.

There is no room for (-5,9) on our graph but if you extended the left hand side of the absolute value function there you would see that (-5,9) is reached.

x=-3

f(-3)=|3--3|+1=|3+3|+1=|6|+1=6+1=7.

(-3,7) should be a point on the graph. Same thing for this point as (-5,9).

x=-1

f(-1)=|3--1|+1=|3+1|+1=|4|+1=4+1=5.

(-1,5) is located on the graph.

x=0

f(0)=|3-0|+1=|3|+1=3+1=4.

(0,4) is also located on the graph.

x=1

f(1)=|3-1|+1=|2|+1=2+1=3.

(1,3) is located on the graph.

x=3

f(3)=|3-3|+1=|0|+1=0+1=1.

(3,1) is located on the graph.

x=5

f(5)=|3-5|+1=|-2|+1=2+1=3.

(5,3) is located on the graph.

Now if we weren't given the graph already:

I would plot the points I found which were:

(-5,9)

(-3,7)

(-1,5)

(0,4)

(1,3)

(3,1)

(5,3)

We should get a basic idea of what the function looks like from these points.

I will graph them. You will have to connect these points because the domain isn't discrete like number 12 is.  That is they didn't list out elements for the domain.

I'm going to graph one more point after x=5.

How about x=7?

f(7)=|3-7|+1=|-4|+1=4+1=5

So (7,5) is also a point on the graph.

You should see that the blue points are following the red path I made there.

8 0
3 years ago
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