Mean- 2
median- 2
mode- 1&2
range- 3
4)
the arrow touches the ground when the heigth is 0
so we need to replace h=0 and solve for t
<em>the arrow tuches the ground at 3.4 seconds</em>
5)
replacing
<em>solve for m</em>
<em>the mass is 13.50Kg</em>
<em />
Its 6. 4 x 6 = 24 so multiply 1 by 6 and thats your answer
Answer:
8 x^5 y^7
Step-by-step explanation:
Simplify the following:
4×2 x^2 y^3 x^3 y^4
Hint: | Combine products of like terms.
4 x^2 y^3×2 x^3 y^4 = 4 x^(2 + 3) y^(3 + 4)×2:
4×2 x^(2 + 3) y^(3 + 4)
Hint: | Evaluate 3 + 4.
3 + 4 = 7:
4×2 x^(2 + 3) y^7
Hint: | Evaluate 2 + 3.
2 + 3 = 5:
4×2 x^5 y^7
Hint: | Multiply 4 and 2 together.
4×2 = 8:
Answer: 8 x^5 y^7
2 and 3
Because 11/4 as a mixed number is 2 3/4 its closer to 3 and close to 2.
So it lies between 2 and 3
