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qwelly [4]
2 years ago
15

sorry again for asking this but can someone explain this and give me the answer. Been having a hard time learning this.

Mathematics
1 answer:
Rudik [331]2 years ago
3 0

<em>Hey</em><em>!</em><em>!</em><em>!</em>

<em>In</em><em> </em><em>ques</em><em>tion</em><em> </em><em>no</em><em>.</em><em>4</em><em>,</em><em> </em><em>we</em><em> </em><em>have</em><em> </em><em>to </em><em><u>subtract</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>equation</u></em><em><u>.</u></em>

<em>In</em><em> </em><em>ques</em><em>tion</em><em> </em><em>no</em><em>.</em><em>5</em><em> </em><em>we</em><em> </em><em>have</em><em> </em><em>to</em><em><u> </u></em><em><u>add</u></em><em><u> </u></em><em><u>the </u></em><em><u>equation</u></em><em><u>.</u></em>

<em>Hope </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em>

<h3><em><u>Have</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>great</u></em><em><u> </u></em><em><u>day</u></em></h3>
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Answer

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Step-by-step explanation:

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3 years ago
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Addison earn $25 mowing her neighbor's lawn then she loaned her friend $18 and got 50 from her grandmother for her birthday she
yarga [219]

Solution: The total money did addison have to begin with is $29.

Explanation:

Let the addison begin with money $x.

It is given that the addison earn $25 from his neighbor and $50 from her grandmother. So total money addison has \$x+\$25+\$50=\$x+\$75

She loaned her friend %18.

Now she has \$x+\$75-\$18=\$x+\$57

It is given that she had $86.

\$x+\$57=\$86\\\$x=\$86-\$57\\\$x=\$29

Therefore, the total money did addison have to begin with is $29.

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3 years ago
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You invested $5000 between two accounts paying 2% and 4% annual interest, respectively. If the total interest earned for the yea
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You invested $5000 between two accounts paying 2% and 4% annual interest, respectively. If the total interest earned for the year was $160, how much was invested at each rate? $ was invested at 2% and was invested at 4%.

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2 years ago
(a) Use the power series expansions for ex, sin x, cos x, and geometric series to find the first three nonzero terms in the powe
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Answer:

a) \mathbf{4 + \dfrac{x}{1!}- \dfrac{2x^2}{2!}  ...}

b)  See Below for proper explanation

Step-by-step explanation:

a) The objective here  is to Use the power series expansions for ex, sin x, cos x, and geometric series to find the first three nonzero terms in the power series expansion of the given function.

The function is e^x + 3 \ cos \ x

The expansion is of  e^x is e^x = 1 + \dfrac{x}{1!}+ \dfrac{x^2}{2!}+ \dfrac{x^3}{3!} + ...

The expansion of cos x is cos \ x = 1 - \dfrac{x^2}{2!}+ \dfrac{x^4}{4!}- \dfrac{x^6}{6!}+ ...

Therefore; e^x + 3 \ cos \ x  = 1 + \dfrac{x}{1!}+ \dfrac{x^2}{2!}+ \dfrac{x^3}{3!} + ... 3[1 - \dfrac{x^2}{2!}+ \dfrac{x^4}{4!}- \dfrac{x^6}{6!}+ ...]

e^x + 3 \ cos \ x  = 4 + \dfrac{x}{1!}- \dfrac{2x^2}{2!} + \dfrac{x^3}{3!}+ ...

Thus, the first three terms of the above series are:

\mathbf{4 + \dfrac{x}{1!}- \dfrac{2x^2}{2!}  ...}

b)

The series for e^x + 3 \ cos \ x is \sum \limits^{\infty}_{x=0} \dfrac{x^x}{n!} +  3 \sum \limits^{\infty}_{x=0} ( -1 )^x  \dfrac{x^{2x}}{(2n)!}

let consider the series; \sum \limits^{\infty}_{x=0} \dfrac{x^x}{n!}

|\frac{a_x+1}{a_x}| = | \frac{x^{n+1}}{(n+1)!} * \frac{n!}{x^x}| = |\frac{x}{(n+1)}| \to 0 \ as \ n \to \infty

Thus it converges for all value of x

Let also consider the series \sum \limits^{\infty}_{x=0}(-1)^x\dfrac{x^{2n}}{(2n)!}

It also converges for all values of x

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masha68 [24]

Answer:

17

Step-by-step explanation:

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