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3 years ago

Can someone help with the equation(s)?

Mathematics

1 answer:

777dan777 [17]3 years ago

8 0

Answer:

Ok this is multiplication so its 30.25

Step-by-step explanation:

5.50 X 5.50 = 30.25

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I would like to know how to do this problem

____ [38]

Answer:

y = 1/3 x + 7

Step-by-step explanation:

Parallel line has same slope

x - 3y = 21

y = 1/3 x -7 slope = 1/3

pass point (-6 , 5)

y = mx + b m: slope b: y intercept y = 5 x = -6

b = y - mx = 5 - (1/3 x (-6)) = 7

equation: y = 1/3 x + 7

5 0

3 years ago

ralph is three times as old as sarah. in 6 years ralph will be twic as od as sarah will be then find ralphs age now

frutty [35]

1) 3S = R 2) R+6= 2 (S+6)= 2S+12 ----> R=2S+61,2 )--> 3S = 2S+6 ---><span>S=6 & R= 3 x 6 = 18Ralph is 18 & Sara is 6 .</span>

8 0

3 years ago

Question 1. If the perimeter of Rectangle ABCD is 34y+2. What is the width?

Savatey [412]

Answer:

Question 1. If the perimeter of Rectangle ABCD is 34y+2. What is the width?

Question 2. What is the area of Rectangle ABCD in terms of y?

Question 3. If the perimeter of the rectangle is 70. What is it’s area?

Question 4. What are the length and width of the rectangle?

6 0

3 years ago

Without using a calculator, choose the statement that the best describes the value of 24. Help me please...

Viktor [21]

Answer:

Step-by-step explanation:

check the answer,4 square=16,

4.5 square=20.25,

5 square=25

20.25<24<25,

so 4.5<square root of 24<5

6 0

3 years ago

Pythagorean triples are given by the formulas x2 - y2, 2xy, and x2 + y2. Use the formulas for the Pythagorean triples to prove w

Arte-miy333 [17]

Let $k$ be an integer. Suppose there is a triangle with legs of length 16 and $2k+1$ . Then by the Pythagorean theorem, the length of the hypotenuse should be

$\sqrt{16^2+(2k+1)^2}=\sqrt{4k^2+4k+257}$

The formulas for Pythagorean triples say that if the legs are integers, then so must be the hypotenuse, because if $x=16$ and $y=2k+1$ are integers, then so are $x^2-y^2$ , $2xy$ , and $x^2+y^2$ .

However, $4k^2+4k+257$ is not a perfect square trinomial, which means for any integer $k$ , the length of the hypotenuse is not an integer, so such a triangle doesn't exist.

4 0

3 years ago