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svlad2 [7]
3 years ago
12

15 POINTS PLZ HELP please look at the images below

Physics
1 answer:
Daniel [21]3 years ago
3 0

Answer:

A incresing speading up

Explanation:

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Which chemical reaction releases the most energy?
IceJOKER [234]
A.nuclear chain reaction
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A person who has a job that requires working all night and sleeping during the day will end up fighting hos or her natural
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Answer:

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The answer to this question is circadian rhythm. A person who has a job that requires working all night and sleeping during the day will end up fighting his or her natural circadian rythm. Hope it helps!

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4 years ago
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Two sites are being considered for wind power generation. In the first site, the wind blows steadily at 7 m/s for 3000 hours per
slavikrds [6]

Answer:

E.year₂ > E.year₁  (Second site is better)

Explanation:

Given data

V_{1}=7 m/s\\Time_{1}=3000 hours/year\\V_{2}=10m/s\\Time_{2}=1500hours/year

The  power generation is the time rate of kinetic energy which can be calculated as:

Power=ΔKE=m×V²/2

Regarding  that m ∝ V.Then

Power ∝ V³ ⇒ Power=constant×V³

Since ρa is constant for both sides and Area is the same as same wind turbine is used

For First site

Power_{1}=const.V^3\\Power_{1}=const.(7m/s)^3\\Power_{1}=const.343Watt\\

For second site

Power_{2}=const.V_{2}^3\\Power_{2}=const.(10m/s)^3\\Power_{2}=const.1000W

Calculating energy generation per year for each of two sites

E.year=Power×Operation time per year

For First site

E.year₁=Power₁×Operation time₁ per year

E_{year1}=const.*343W*3000\\E_{year1}=const.1029000(W.hour/year)

For Second site

E.year₂=Power₂×Operation time₂ per year

  E_{year2}=const.*1000W*1500\\E_{year2}=const.1500000(W.hour/year)

So

E.year₂ > E.year₁  (Second site is better)

3 0
4 years ago
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Someone please help with this
SSSSS [86.1K]

Answer:

<em>The new force is 2/3 of the original force</em>

Explanation:

<u>Coulomb's Law </u>

The electrical force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.

Written as a formula:

\displaystyle F=k\frac{q_1q_2}{d^2}

Where:

k=9\cdot 10^9\ N.m^2/c^2

q1, q2 = the objects' charge

d= The distance between the objects

Suppose the first charge is doubled (2q1) and the second charge is one-third of the original charge (q2/3). Now the force is:

\displaystyle F'=k\frac{2q_1*q_2/3}{d^2}

Factoring out 2/3:

\displaystyle F'=\frac{2}{3}k\frac{q_1*q_2}{d^2}

Substituting the original force:

F'=\frac{2}{3}F

The new force is 2/3 of the original force

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In physics, the three types of acceleration are changes in velocity (speed), changes in direction or changes in both
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