Question

Water has a specific heat of 4.186 J/g°C. How much heat is required to increase 10.0 g of water from 25.0°C to 30.0°C?

Answer 1

10 x 4.186 x (30-25)=209 j

Answer 2

Answer: D) 209 Joules

Explanation:

Using the equation below:

$Q= m\times c\times \Delta T$

Q= heat gained

m= mass of the substance = 10.0 g

$\Delta T$  = change in temperature =$(30-25)^0C=5^0C$

c = heat capacity of water = 4.186 J/g ° C      

Putting in all the values we get:

$Q=10g\times 4.186J/g^0C\times 5^0C$

$Q=209Joules$

Thus heat gained by 10 g of water is 209 Joules