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3 years ago

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A hydraulic lift has two connected pistons with cross-sectional areas 15 cm2 and 670 cm2. It is filled with oil of density 510 k

g/m3.
What mass must be placed on the small piston to support a car of mass 1100 kg at equal fluid levels?

1 answer:

BigorU [14]3 years ago

4 0

Answer:

Explanation:

Given

Cross-sectional area of two areas is

$A_1=15\ cm^2$

$A_2=670\ cm^2$

It is filled with oil of density $\rho _0=510\ kg/m^3$

mass of car place on Large area $M=1100\ kg$

Suppose a mass of m kg is placed on smaller area

According to pascal law's intensity of pressure is same at every point on Liquid

$P_1=P_2$

$\frac{F_1}{A_1}=\frac{F_2}{A_2}$

$\frac{mg}{15}=\frac{Mg}{670}$

$m=1100\times \frac{15}{670}$

$m=24.62\ kg$

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The final velocity of the object, $v_{f}$ = ?

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v = ( $x_{f}$ - $x_{i}$ )/ t

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