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RoseWind [281]
3 years ago
5

A hydraulic lift has two connected pistons with cross-sectional areas 15 cm2 and 670 cm2. It is filled with oil of density 510 k

g/m3.
What mass must be placed on the small piston to support a car of mass 1100 kg at equal fluid levels?
Physics
1 answer:
BigorU [14]3 years ago
4 0

Answer:

Explanation:

Given

Cross-sectional area of two areas is

A_1=15\ cm^2

A_2=670\ cm^2

It is filled with oil of density \rho _0=510\ kg/m^3

mass of car place on Large area M=1100\ kg

Suppose a mass of m kg is placed on smaller area

According to pascal law's intensity of pressure is same at every point on Liquid

P_1=P_2

\frac{F_1}{A_1}=\frac{F_2}{A_2}

\frac{mg}{15}=\frac{Mg}{670}

m=1100\times \frac{15}{670}

m=24.62\ kg                            

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Answer:

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