Foolish, ambiguous question, with no correct answer, but at a wild guess, it MIGHT wobble about it own axis????
Answer:
The velocity at impact is 222.2 m/s
Explanation:
The given information are;
The time at which the woman heard the sound of the coin after dropping it into the wishing well = 30 seconds
The average speed of sound in air = 344 m/s
The time in which the dime travel = t₁
The time in which the sound travel = t₂
1/2 × 9.8 × t₁² = 344 × t₂
t₁ + t₂ = 30
4.9·t₁² = 344 × (30 - t₁)
4.9·t₁² + 344·t₁ - 10320 = 0
Which gives -344±

t₁ = 22.676 seconds or -92.9 seconds
Therefore the correct natural time is t₁ = 22.676 seconds
The velocity at impact, v = g×t₁ = 9.8 × 22.676 = 222.2 m/s
The velocity at impact= 222.2 m/s.
Answer:
5.865 μs
Explanation:
t₀ = Time taken to decay a muon = 2.20 μs
c = Speed of Light in vacuum = 3×10⁸ m/s
v = Velocity of muon = 0.927 c
t = Lifetime observed
Time dilation

∴Lifetime observed for muons approaching at 0.927 the speed of light is 5.865 μs
Answer:
They two waves has the same amplitude and frequency but different wavelengths.
Explanation: comparing the wave equation above with the general wave equation
y(x,t) = Asin(2Πft + 2Πx/¶)
Let ¶ be the wavelength
A is the amplitude
f is the frequency
t is the time
They two waves has the same amplitude and frequency but different wavelengths.