How many roots does the graphed polynomial function have? A. 4 B. 3 C. 1 D. 2

On a coordinate plane, point A is at (3, 3) and point B is at (negative 3, 3). Point B is the image of point A when A is rotated

Vladimir [108]

Answer:

Point B must be at the same distance from the the origin as point A.

Step-by-step explanation:

Coordinates of point A = (3, 3)

When point A is rotated 90° counterclockwise around the origin, coordinates of the new point B will be (-3, 3)

Distance from origin to point A = $\sqrt{(3)^{2}+(3)^2}=3\sqrt{2}$

Similarly, distance of point B from the origin = $\sqrt{(3)^{2}+(3)^2}=3\sqrt{2}$

Therefore, distances of both the points from the origin are same.

Point B must be at the same distance from the the origin as point A.

7 0

3 years ago

Solve 3/4x = 7 28/ 3

Olegator [25]

3/4x=728/3

x=728/3×4/3

x=32.556

HOPE IT HELPS YOU OUT PLEASE MARK IT AS BRAINLIEST AND FOLLOW ME PROMISE YOU TO FOLLOW BACK ON BRAINLY.IN

BUT I'M NOT SURE IF IT IS CORRECT

6 0

2 years ago

Write an expression that can be usedto find the nth termo of each sequence 9, 17, 25, 33

ra1l [238]

Answer:

The expression used to find the nth term of each sequence 9, 17, 25, 33 will be:

$a_n=8n+1$

Step-by-step explanation:

Given the sequence

9, 17, 25, 33

a₁ = 9

Determining the common difference

d = 17-9 = 8

d = 25-17 = 8

d = 33-25 = 8

As the common difference between the adjacent terms is same and equal to

d = 8

Therefore, the given sequence is an Arithmetic sequence.

An arithmetic sequence has a constant difference 'd' and is defined by

$a_n=a_1+\left(n-1\right)d$

substituting a₁ = 9, d = 8 in the equation

$\:a_n=9+8n-8$

$a_n=8n+1$

Therefore, the expression used to find the nth term of each sequence 9, 17, 25, 33 will be:

$a_n=8n+1$

6 0

2 years ago

The ratio of teachers to students in a school is 1:18.

sineoko [7]

Answer:

if there are 360 students, the number of teacher will be 6,480...

360:6,480

6 0

2 years ago

Read 2 more answers

A mixture of compounds X and Y in a 0.100-cm cell had an absorbance of 0.215 at 272 nm and 0.191 at 327 nm. Find [X] and [Y] in

Oksi-84 [34.3K]

Answer: The concentration of X is $7.13582\times 10^{-6}$ and the concentration of Y is $2.53159\times 10^{-5}$ .

Step-by-step explanation:

Since we have given that

At 272 nm, absorbance = 0.215

At 327 nm, absorbance = 0.191

As we have given that

Compound X Compound Y

272 16400 3870

327 3990 6420

So, our equations becomes

$16400C_1+3870c_2=0.215\\\\3990C_1+6420C_2=0.191$

By solving these two equations, we get that

$C_1=7.13582\times 10^{-6}\\\\C_2=2.53159\times 10^{-5}$

Hence, the concentration of X is $7.13582\times 10^{-6}$ and the concentration of Y is $2.53159\times 10^{-5}$ .

5 0

3 years ago