materials with a density less than water will float
Answer:
3.84 m/s
Explanation:
Using Bernoulli's equation below:
P1 + (1/2ρv1²) + h1ρg = P2 + (1/2ρv2²) + h2ρg
where P1 = P2 atmospheric pressure
(1/2ρv1²) + h1ρg = (1/2ρv2²) + h2pg
collect the like terms
h1ρg - h2ρg = (1/2ρv2²) - (1/2ρv1²)
factorize the expression by removing the like terms on both sides
gρ(h1 - h2) = 1/2ρ( v2² - v1²)
divide both side by rho (density in kg/m³, ρ )
g(h1 - h2) = 1/2 (v2² - v1²)
assuming the surface of the tank is large and the speed of water then at the tank surface v1 = 0
2g(h1 - h2) = v2²
take the square root of both side and h1 - h2 is the difference between the surface of the tank and the opening where water is coming out in meters
√2g(h1 - h2) = √ v2²
v2 = √2g(h1-h2) = √ 2 × 9.81×0.75 = 3.84 m/s
F3 -4 wouldn’t even be a guhd add up tbsh jus delete it
Answer:
Explanation:
Let the shells speed with respect to ground be 
Let the shells speed with respect to ground be 
mass of shell, 
mass of gun, 
The relative velocity of shell with respect to a free unconstrained gun, 
According to the Newton's third law of motion the direction of the velocity of gun and shell will be in the opposite direction.
So, the relation between the relative velocity and their individual velocity will be:
......................(1)
<u>And according to the conservation of momentum (as the condition is very close to the elastic collision):</u>
substitute the value of from equation (1)
answer choices?
like can you give a little more info regarding your question please and thank you
