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2 years ago

Atomic math challenge will give brainly and thanks

Physics

2 answers:

nevsk [136]2 years ago

8 0

Answer:

1. Hydrogen

Atomic # = 1

Atomic Mass = 1.00794 ( If you round it it's 1.008 )

# of protons = 1

# of neutrons = none

# of electrons = 1

WARRIOR [948]2 years ago

8 0

Had the same exact question

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A comet is first seen at a distance of d astronomical units from the Sun and it is traveling with a speed of q times the Earth’s

saw5 [17]

To solve this problem it is necessary to take into account the concepts of Gravitational Force and Kinetic Energy.

The kinetic energy is given by the equation:

$F= \frac{mv^2}2$

La energía gravitacional por,

$F=\frac{GM_cm}{d}$

Where m is the mass, v is the velocity, G the gravitational constant $M_e$ the mass of the earth, m the mass of the sun and d the distance ..

The sum of the energies, we must be a total energy

$E= \frac{mv^2}2+\frac{GM_em}{d}$

By the type of orbit we know that

E> 0 is a hyperbolic orbit

E = 0 is a parabolic orbit

E <0 is a closed orbit.

In the case of hyperbolic orbit

E>0

$\frac{mq^2}{2}-\frac{GM_em}{d}>0\\\frac{qv^2_e}{2}>\frac{GM_em}{d}\\q^2d>2\frac{GM_e}{v^2_e}\\q^2d>2$

The case of the comet is a closed orbit, so,

E<0

$\frac{mv^2}2+\frac{GM_em}{d}$

For parabolic orbit

E=0

$\frac{mv^2_eq^2}{2}-\frac{GM_cm}{d}=0\\\frac{v^2_eq^2}{2}=\frac{GM_c}{d}\\q^2d=2\frac{GM_e}{v^2_e}\\q^2d=2$

For the sun and the earth

$\frac{m_ev_e^2}{r}=\frac{GM_em_e}{r^2}$

$v^2_e=\frac{GM_e}{r}\\\frac{GM_e}{v_e}=r$

where $R \approx 1AU$

$q^2d$ For elliptical orbit

8 0

3 years ago

Using our understanding of the law of gravity. What happens to the gravity as we triple the distance between two objects?

MA_775_DIABLO [31]

Answer:

1/9

Explanation:

<em>Newton’s Law of Universal Gravitation </em>

Objects with mass feel an attractive force that is proportional to their masses and inversely proportional to the square of the distance.

F = GMm/r²

where

F - the gravitatioal force in Newtons,

M and m -two masses in kilograms

r - the separation in meters.

G - the gravitational constant (6.674*10 ⁻¹¹ N (m/kg) ² )

Because of the magnitude of G , gravitational force is very small unless large masses are involved.

So according to above equation , when the masses are not changing , force is inversely propotional to the square of distance

F1 ∝ 1/r² ---------------(1)

F2 ∝ 1(3r)²

F2 ∝ 1/9r²--------------(2)

(2)/(1)

$\frac{F_2}{F_1} =\frac{1}{9}\\ F_2 =\frac{F_1}{9}$

From their you get as the distance tripled, Force reduce by a factor of 9(3³)

for example , assume the distance get doubled ,Force reduce by a factor of 4 (2²)

3 0

3 years ago

For a neutrally charged atom, which of these must be true?

Darina [25.2K]

The number of electrons is equal to the number of protons.

7 0

3 years ago

A constellation’s changing position in the sky, at the same time of the evening, over a period of several weeks is evidence that

Goryan [66]

Answer:

d- Earth revolves around the sun.

Explanation:

Earth rotation can be defined as the amount of time taken by planet earth to complete its spinning movement on its axis.

This ultimately implies that, the rotation of earth refers to the time taken by earth to rotate once on its axis. One spinning movement of the earth on its axis takes approximately 24 hours to complete with respect to the sun.

On the other hand, earth revolution can be defined as a complete trip along a path around the sun. This path is known as an orbit and it typically takes the Earth 365¼ days to complete it's journey around the Sun.

When a constellation (stars) changes its position in the sky, at the same time of the evening and over a period of several weeks; it ultimately implies or is an evidence that Earth revolves around the sun.

8 0

2 years ago

Consider a uniform hoop of radius r and mass m rolling without slipping. which is larger, its translational kinetic energy or it

OlgaM077 [116]

<span>translational kinetic energy is larger than its rotational kinetic energy</span>

3 0

2 years ago