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Romashka [77]
1 year ago
12

How much magnetic potential energy is dissipated when the magnetic field is quenched in this way?

Physics
1 answer:
Lunna [17]1 year ago
3 0

Energy is 4 * 10^{5} J

The rate of dissipation is 2 * 10^{4} W

In the question, it is given that

t = 20 s

R = 400 mm

L = 300 mm

where t, R, and L are time, radius, and length.

For magnetic energy density, the formula is

ηo = Energy / volume

     = β^2 / 2 * μ

Now, substituting the values

 = 2^{2} / 2 * 4 * Π * 10^{-7}

 = 1.59 * 10^{-6} J / m^3

Now, energy is

= energy density * volume

= 1.59 * 10^{-6} *  Π * 0.5 * 0.4^{2}

= 4 * 10^{5} J

The rate of dissipation is

= Energy / time

=  4 * 10^{5} / 20

= 2 * 10^{4} W

For more information click on the link below:

brainly.com/question/7802337

# SPJ4

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A rock falls from rest off a cliff and hits the ground in 2 seconds. If there is no air resistance, determine the rock's velocit
mihalych1998 [28]

Answer:

19.6m/s

Explanation:

A Rock falling off a cliff can be modeled as an object starting with  zero velocity moves with constant acceleration for certain period of time, for such motion following equation of motion can be used.

v(t) = v_{0} +at

here in our case v_{0} =0 because object starts off from rest and a = g =9.8m/s^2 is acceleration because of gravity ( Motion under gravity).

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Now by substituting all this information in equation of motion we get.

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that would be the velocity of rock as it would hit the ground.

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A rock falling off a cliff can be modeled as an object starting with zero velocity moves with constant acceleration for a certain period of time, for such motion following equation of motion can be used.

here in our case  because object starts off from rest and  is acceleration because of gravity ( Motion under gravity).

and of course t = 2 seconds.

Now by substituting all this information in equation of motion we get.

V = 19.6m/s

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Note! We have assumed that there is no air resistance.

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