Question

How much magnetic potential energy is dissipated when the magnetic field is quenched in this way?

Answer 1

Energy is 4 * $10^{5}$ J

The rate of dissipation is 2 * $10^{4}$ W

In the question, it is given that

t = 20 s

R = 400 mm

L = 300 mm

where t, R, and L are time, radius, and length.

For magnetic energy density, the formula is

ηo = Energy / volume

     = β^2 / 2 * μ

Now, substituting the values

 = $2^{2}$ / 2 * 4 * Π * $10^{-7}$

 = 1.59 * $10^{-6}$ J / m^3

Now, energy is

= energy density * volume

= 1.59 * $10^{-6}$ *  Π * 0.5 * $0.4^{2}$

= 4 * $10^{5}$ J

The rate of dissipation is

= Energy / time

=  4 * $10^{5}$ / 20

= 2 * $10^{4}$ W

For more information click on the link below:

brainly.com/question/7802337

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