Displacement from the center line for minimum intensity is 1.35 mm , width of the slit is 0.75 so Wavelength of the light is 506.25.
<h3>How to find Wavelength of the light?</h3>
When a wave is bent by an obstruction whose dimensions are similar to the wavelength, diffraction is observed. We can disregard the effects of extremes because the Fraunhofer diffraction is the most straightforward scenario and the obstacle is a long, narrow slit.
This is a straightforward situation in which we can apply the
Fraunhofer single slit diffraction equation:
y = mλD/a
Where:
y = Displacement from the center line for minimum intensity = 1.35 mm
λ = wavelength of the light.
D = distance
a = width of the slit = 0.75
m = order number = 1
Solving for λ
λ = y + a/ mD
Changing the information that the issue has provided:
λ = 1.35 * 10^-3 + 0.75 * 10^-3 / 1*2
=5.0625 *10^-7 = 506.25
so
Wavelength of the light 506.25.
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Answer:
4.19 km and 107.35 degrees north of east
Explanation:
So in the end, the truck is (2.6 + 1.4 = 4km) north and 1.25 km west from the warehouse. We can use the Pythagorean formula to calculate the magnitude and direction α of the truck displacement from the warehouse:
km
north or west or (180 - 72.65) = 107.35 degrees north of east
Answer:
Wavelength λ = 7.31 × 10^-37 m
Explanation:
From De Broglie's equation;
λ = h/mv
Where;
λ = wavelength in meters
h = plank's constant = 6.626×10^-34 m^2 kg/s
m = mass in kg
v = velocity in m/s
Given;
v = 24 mi/h
Converting to m/s
v = 24mi/h × 0.447 m/s ×1/(mi/h)
v = 10.73m/s
m = 84.5kg
Substituting the values into the equation;
λ = (6.626×10^-34 m^2 kg/s)/(84.5kg × 10.73m/s)
λ = 7.31 × 10^-37 m
