What is the product of 23 and 18?

PLEASE HELP ME WITH THIS PROBLEM ASAP

lana [24]

Answer:

15x+5+22x+4+60=180

37x=180-60-5

37x=115

x=115/37

x=3

angle b

22*3+4=70°

angle c

15*3+5=50°

have a nice day . hope this helps

7 0

2 years ago

I need some help and can you please show your work? Thank you have a good day

SVEN [57.7K]

$1.75

If 4 lemons altogether cost $7, you want to divide the price by 4 to find the price for one single lemon.

7/4 = $1.75

Now if you buy 4 lemons that cost $1.75, your total will add up to $7

3 0

3 years ago

1) A cyclist travels a distance of 90 miles in 5 hours. What

Nostrana [21]

Answer:

Step-by-step explanation: <u>Speed</u> is distance an object travelled per unit time.

It is represented by letter v and can assume various units.

1) $v=\frac{distance}{time}=\frac{d}{t}$

$v=\frac{90}{5}$

v = 18 miles per hour

Her average speed is 18 mph.

2) Rearraging formula for distance:

d = v.t

d = 70 * 4

d = 280 miles

You would travel 280 miles.

3) $v=\frac{d}{t}$

$v=\frac{315}{6}$

v = 52.5 mph

My average speed is 52.5 mph.

4) Rearranging formula to determine time:

$t=\frac{d}{v}$

$t=\frac{210}{90}$

t = 2.34 hours

It will take 2 hours and half to arrive in Leeds. So, we will be expected to arrive at 12:04.

5) The unit change but the way of calculating time is the same.

$t=\frac{2000}{4}$

t = 500 s

or t = 8.34 minutes

It will take, for an athlete to run 2000m, 8.34 minutes.

6) a) All units must match, so for a speed in mph:

45 minutes is 0.75 hours. Total time is 8.75 hours.

$v=\frac{420}{8.75}$

v = 560 mph

The average speed is 560 mph.

b) $t=\frac{d}{v}$

$t=\frac{420}{63}$

t = 6.67 hours

Sam will take 6.67 hours to covered the distance.

4 0

2 years ago

A rhombus ABCD has AB = 10 and m∠A = 60°. Find the lengths of the diagonals of ABCD.

melisa1 [442]

Three important properties of the diagonals of a rhombus that we need for this problem are:
1. the diagonals of a rhombus bisect each other
2. the diagonals form two perpendicular lines
3. the diagonals bisect the angles of the rhombus

First, we can let O be the point where the two diagonals intersect (as shown in the attached image). Using the properties listed above, we can conclude that ∠AOB is equal to 90° and ∠BAO = 60/2 = 30°.

Since a triangle's interior angles have a sum of 180°, then we have ∠ABO = 180 - 90 - 30 = 60°. This shows that the ΔAOB is a 30-60-90 triangle.

For a 30-60-90 triangle, the ratio of the sides facing the corresponding anges is 1:√3:2. So, since we know that AB = 10, we can compute for the rest of the sides.

$\overline{OB}:\overline{AB} = 1:2$
$\overline {OB}:10 = 1:2$
$\overline{OB} = \frac{1}{2}(10) = 5$

Similarly, we have

$\overline{AO}:\overline{AB} = \sqrt{3}:2$
$\overline {AO}:10 = \sqrt{3}:2$
$\overline{AO} = \frac{\sqrt{3}}{2}(10) = 5\sqrt{3}$

Now, to find the lengths of the diagonals,

$\overline{AD} = 2(\overline{AO}) = 10\sqrt{3}$
$\overline{BC} = 2(\overline{OB}) = 10$

So, the lengths of the diagonals are 10 and 10√3.

Answer: 10 and 10√3 units