Put the first number on top then start adding 6+0, 8+1, 0+4, 1+1, 0+0 and the answer is 69420
It should be 117.5 because in a kite, the angles all add up to 360, and since the remaining unknown angles are the same, you just subtract 38+87 from 360 and divide by 2
If the problem is supposed to read (4^33*8^37)/(4^15*8^21), then...
(4^33*8^37)/(4^15*8^21) = (4^33/4^15)*(8^37/8^21)
(4^33*8^37)/(4^15*8^21) = 4^(33-15)*8^(37-21)
(4^33*8^37)/(4^15*8^21) = 4^18*8^16
Answer: Choice A) 4^18*8^16
Step-by-step explanation:
Step one:
given
current (older) fridge
electricity charges= $17 monthly
maintenance costs= $220
let the number of months be x
and the total cost be yo
the expression for the cost for the old fridge is
yo=220+17x---------1
New fridge
electricity charges= $6 monthly
costs= $1,050
let the number of months be x
and the total cost be yn
the expression for the cost for the old fridge is
yn= 1050+6x---------2
Hence the system of equation for the situation is
yo=220+17x---------1
yn= 1050+6x---------2
Step two
for 10 years there are 12*10= 120 months
put x= 120 in both expressions and compare the total
yo=220+17(120)---------1
yo=220+2040
yo=$2,260
yn= 1050+6(120)---------2
yn=1050+720
yn=$1770
<u><em>Based on the analysis it will be less expensive to get the new fridge, hence buying the new fridge is worth it.</em></u>
Answer:
b) 690 - 7.5*t
c) 0 < t < 92s time (t) is independent quantity
d) 0 < s < 690ft distance from bus stop (s) is dependent quantity
e) f(0) = 690 ft away from bus stop , f(60.25) = 238.125 ft away from bus stop
Step-by-step explanation:
Part a - see diagram
part b
initial distance from bus stop s0 = 690 ft
distance covered = 7.5*t
s = s0 - distance covered
s = 690 - 7.5*t = f(t)
part c
s = 0 or s = 690
0 = 690 -7.5*t
t = 92 s
Hence domain : 0 < t < 92s time (t) is independent quantity
part d
s = 0 or s = 690
Hence range : 0 < s < 690ft distance from bus stop (s) is dependent quantity because it depends on time (t)
part e
f(0) is s @t = 0
f(0) = 690 ft away from bus stop
f(60.25) is s @t = 60.25
f(60.25) = 690 - 7.5*60.25 = 238.125 ft away from bus stop.
