NO. The mirror will not fit in a space that is 15 inches by 16 inches
<em><u>Solution:</u></em>
Given that area of mirror is 225 square inches
Converting the above mixed fraction we get,
Let us find the length of mirror
The area of mirror is given as:
area of mirror = length x width
Substituting the given values,
Thus length of mirror is 16.36 inches
<em><u>Will the mirror fit in a space that is 15 inches by 16 inches?</u></em>
NO. The mirror will not fit in a space that is 15 inches by 16 inches
Because length of mirror is 16.36 inches whereas the given space is 15 inches long
16.36 > 15 so the length of mirror will not fit inside the space
Also width of mirror is 
inches which is less than the given space whose width is 16 inches
13.75 < 16 so the width of mirror will not fit inside the space
Answer:
C. 15
Step-by-step explanation:
<h2>
<em><u>∠ADC=∠ABC/2=30/2=15</u></em></h2>
Answer:
Hey there!
The range is the possible y values, so the range of this graph would be all real numbers less than or equal to -6.
Let me know if this helps :)
Volume of sphere is given by:
V=4/3πr³
the radius of the sphere will therefore be given by:
5000π=4/3πr³
solving for r we get:
r³=3750
hence
r=15.54 m
the area will therefore be:
A=4πr²
A=4π(15.54)²A=965.49π m²
Answer:
(800 x 9) + (10 x 9)
Step-by-step explanation:
Find out what 810 x 9 is:
810 x 9 = 7290
Then see which expression has the same answer. Personally I'd check all of them, but luckily the first expression is the correct one so you don't need to go through the rest (since it only asks for one correct expression):
(800 x 9) = 7200
(10 x 9) = 90
7200 + 90 = 7290
