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3 years ago

Why does lithium have a higher ionization energy compared to sodium?

Chemistry

1 answer:

frez [133]3 years ago

3 0

Answer:

There are 11 protons in a sodium atom but only 3 in a lithium atom, so the nuclear charge is much greater. ... The only factor left is the extra distance between the outer electron and the nucleus in sodium's case. That lowers the ionization energy.

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A 30.2 mL aliquot of a 30.0 wt% aqueous KOH solution is diluted to 1.20 L to produce a 0.173 M KOH solution. Calculate the densi

alexandr1967 [171]

Answer:

The density of solution is 1.283 g/mL.

Explanation:

Molarity of the KOH before dilution = $M_1$

Volume of the solution before dilution = $V_1=30.2 mL$

Molarity of the KOH after dilution = $M_2=0.173 M$

Volume of the solution after dilution = $V_2=1.20 L=1200 mL$

$M_1V_1=M_2V_2$

$M_1=\frac{M_2V_2}{V_1}=\frac{0.173 M\times 1200 mL}{30.2 mL}$

$M_1=6.8742 M$

$Molarity=\frac{moles}{Volume (L)}$

$V_1=30.2 mL=0.0302 L$ (1 mL = 0.001 L)

$M_1=\frac{n}{V_1}$

$n=M_1\times V_1=6.8742 M\times 0.0302 L=0.2076 mol$

Mass of 0.2076 moles of KOH:

0.2076 mol × 56 g/mol = 11.6256 g

Mass of KOH is solution = 11.6265 g

Mass of the solution = M

Mass percentage of solution = 30.0% of KOH

$30.0\%=\frac{11.6265 g}{M}\times 100$

M = 38.755 g

Density of the solution , d= $\frac{M}{V_1}$

$d=\frac{38.755 g}{30.2 mL}=1.283 g/mL$

The density of solution is 1.283 g/mL.

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