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insens350 [35]
4 years ago
11

Hydrangea plant's petals change to which colour on the addition of acids?

Chemistry
1 answer:
Black_prince [1.1K]4 years ago
4 0
If it's a pH below six it's blue, if it's a pH between 6 and 7 then it would be purple, if it's above 7 it would be pink or red
You might be interested in
Given:
strojnjashka [21]

Answer:

≈ 708

Explanation

Here we have equation as:

                        4 Al     +    3 O₂    →    2 Al₂O₃

As we know:  

                       No of moles = Mass/ Molar mass

Here, Mass is 375 g and Molar mass is 27 gms, so no. of moles of Al will be:

                                            =375 g /27 g/mol

                                               =  13.889 mol

About mole ratio, we can see that for 4 moles of Al , 2 moles of Al2O3 are formed, so for 13.889 moles of Al, 13.889 mol ÷ 2 =6.944 moles of Al₂O₃ will be formed.

As we know:  

                            Mass= No of moles/Molar mass  

                      Mass of Al₂O₃ = 6.944 mol × 102  g/mol

                                           = 708.288 g

Hope it helps!

3 0
4 years ago
I WIll upvote for answer<br> Balance the following reaction Fe^2 O ^3 +HCI-&gt;FeCI^3+H^2O
kotykmax [81]
Fe^2 O^3 + 6HCl --> 2FeCl^3 + 3H^2 O
7 0
3 years ago
Which answer is an isotope of 40/20x? <br><br> Question Pictured here:
Nesterboy [21]

An isotope of ₂₀⁴⁰X  ⇒₂₀⁴⁴X

<h3>Further explanation </h3>

The elements in nature have several types of isotopes

Isotopes are atoms that have the same number of protons and a different number of neutrons.

So Isotopes are elements that have the same Atomic Number (Proton)

In the following element notation,

\large {{{A} \atop {Z}} \right X}

X = symbol of elemental atom

A = mass number

  = number of protons + number of neutrons

Z = atomic number

   = number of protons = number of electrons, on neutral elements

For symbol of isotope X :

₂₀X⁴⁰ : atomic number = 20, mass number = 40

A. ₄₀²⁰X : atomic number = 40, mass number = 20, neutrons=20

B. ₂₀⁴⁰X²⁺ : atomic number = 20, mass number = 40, neutrons=20

C. ₂₁⁴⁰X : atomic number = 21, mass number = 40, neutrons=19

D. ₂₀⁴⁴X : atomic number = 20, mass number = 44, neutrons=22

7 0
3 years ago
If a lab group were using hydrochloric acid to perform a substitution reaction, which precaution would not be a concern?
Pie
The question is incomplete. Complete question is attached below:
...............................................................................................................................

Correct Answer: Option A i.e Flammability

Reason:

Hydrochloric acid is a strong acid. It has a high value of dissociation constant. Following equilibrium is established with HCl is dissolved in water

           HCl     +       H2O           ↔          Cl-     +         H3O+

Above, reaction is highly exothermic in nature. So care must be taken while preparing HCl solution of desired concentration. HCl must be added in beaker containing water. Reversed, i.e. adding water in HCl, must never be done. This is because when acid is poured into water, it flows down the flask and mixes much efficiently and no boiling occurs. On other hand, <span> when water is added to acid, the very first drop of water will react with acid. The heat generated during this event might be high enough to boil the water instantly, which could spray acid out of the container.

The physical contact with concentration HCl will result in skin burn. As well, inhaling</span><span> HCl vapors can cause burns to body tissues, lung damage and even death in extreme cases. Also, since HCl is a strong acid, it would undergoes reaction almost spontaneously, which would inturn favour substitution reaction. However, HCl is not a flammable gas. Hence, it is of no concern while performing substitution reaction.  </span>

4 0
3 years ago
Read 2 more answers
Compound a has molecular formula c5h10. hydroboration-oxidation of compound a produces 2-methylbutan-1-ol. draw the structure of
maw [93]
To help you answer this question, you can search a sample reaction in the internet for hydroboration-oxidation. Take a look at the attached picture. The sample reaction is shown at the top. We can deduce that the original compound must be an alkene. Following the pattern, compound a must be 2-methylbutene as shown in the picture.

8 0
4 years ago
Read 2 more answers
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